Obtaining Zinc Oxide from Calamine

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Obtaining Zinc Oxide from Calamine

Introduction

   Calamine is a mineral containing zinc carbonate (ZnCO) On heating it decomposes as:

ZnCO           ZnO   +   CO

(C = 12, 0 = 16, Zn = 65)

  This equation allows you to calculate a theoretical conversion of calamine into zinc oxide. As when using the theoretical conversion;

ZnCO                              ZnO  +  CO

65+12+48                         65+16   +  12+32

125                                    81   +  44

  This means that one mole of calamine weighs 125g and when heated it produces 81g of zinc oxide and 44g of carbon dioxide. Therefore to work out how much zinc oxide is produced from 1g of calamine we divide 81 by 125.

81/125  =  0.648g

   To calculate how much zinc oxide is produced from 2g of calamine 0.648 is doubled:

0.648 x 2  = 1.296g

  To calculate how much zinc oxide is produced from 3g of calamine 0.648 is tripled and so on when increasing the mass of calamine. On the next page there is a table of the theoretical conversions for how much zinc oxide is produced from using certain amounts of calamine (1g-9g)

 Here is a graph of the results predicted from the table…………

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  This experiment is going to see how much zinc oxide can be obtained from calamine. It shall also show how close to the conversion can be achieved in practice.

Hypothesis

   In a previous experiment where copper carbonate was obtained from malachite the results showed that as the more malachite was used the more product was produced. The relationship between the mass of malachite used and the amount of copper oxide obtained was proportional. Malachite and calamine are next to each other in the periodic table and therefore are alike so I predict that the ...

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