Solution Solution
When the concentration of water molecules of the outside of the cell plant is the same as the inside of the cell plant, the cell remains the same because nothing is happening as both sides are the same so nothing will happen, this is called isotonic, this is when both sides are the same and have the same number of molecules.
Dilute Cell has
Cell Dilute gone smaller
Sugar Sugar (Shriveled up)
Solution Solution
Plasmolysis
Plasmolysis occurs when a plant cells membrane shrinks away from its cell wall. This incident occurs when water is drawn out of the cell into the extra cellular (outside cell) fluid. The movement of water occurs across the membrane moving from an area of high water concentration to an area of lower water concentration outside the cell.
Plant cells where the water flow into the cell and out of the cell are in equilibrium are not capable of providing the cell with support, this term is called flaccid, where it indicates that the cell, although it contains water does not enough inner turgor pressure to provide structural support.
Turgor is the build up of water within the plant cell. Because of the inflexibility of the cell wall the cell does not rupture, but instead the inside pressure increases. This increase pressure gives the plant cells structure that can support the plant.
This is what I expect the stronger solutions to do, take the sugar solution out of the potato instead of it being put into the potato. The potato will therefore shrink.
Diffusion
Diffusion is the movement of molecules from region in which they are highly concentrated to a region in which they are less concentrated. It depends on the motion of the molecules and continues until the system in which the molecules are found reaches a state of equilibrium, which means that the molecules are randomly distributed throughout the system.
Diffusion can also occur through a cell membrane. The membrane allows water, oxygen, carbon dioxide and others to pass through easily. It is said to be permeable to these molecules.
Osmosis is a special case of diffusion. Molecules move from an area of high concentration to an area of low concentration. The movement of molecules towards an area explains this with the least amount of resistance to flow. This movement of molecules from an area of high concentration to that of a low concentration is called diffusion.
This is what I expect my experiment to includes as when my potato is in the sugar solution the solution will go inside the cell as well as going outside at the same rate, however if the potato uses some of the sugar solution as it comes in the potato, more sugar solution will move into the cell rather than move out. So again this is part of osmosis as the sugar solution moves from a region of high concentration into a low concentration, this is also when diffusion occurs.
Equilibrium
There are two types of equilibrium-:
- Static equilibrium- Occurs when no action is taking place
- Dynamic equilibrium- Occurs when two opposing actions are taking place at the same rate.
For example, consider my potato; it is in the state of static equilibrium because the potato stays the same. The potato is not moving or being changed. If you were to add sugar solution then the potato would change, as it would react. This system would not be at equilibrium because there is action-taking place –there is sugar solution with the potato– and the potato would change, as it would react with the sugar solution.
However, if you were to take the sugar solution out of the beaker at the same rate that it was being put in, the potato would stay the same because the rate at which the sugar solution is entering the beaker is the equal to the rate at which it is being put in so there would end up being mo sugar solution leaving the potato like it was in the first place. This is an example of dynamic equilibrium.
Introduction
The aim of this investigation is to find out what happens to potato chips placed in a variety of different concentration of sugar solution and when the chip is placed in to distilled water.
The mass of the potato tube that will be used to judge the degree of osmosis taking place, because 2M is concentrated than 1M meaning that it will have more sugar as the 1M will have less sugar because it is less concentrated.
I will measure the mass of the potato accurately by the nearest g, by also using 2 decimal places 0.1g to make it more accurate.
PLANNING
The variable, which I will be testing, is the concentration and I will be changing the concentration of the sugar solution, I will also be testing distilled water.
I will use distilled water and sugar solution of: -
Distilled water
0.2M
0.4M
0.6M
0.8M
1.0M
2.0M
The higher the molarity of the solution the higher the concentration of the solution will be because the less the number of water molecules which means that there are more sugar molecules present therefore it will be stronger, for e.g. 2.0M is stronger than 0.1M.
I will keep this experiment safe by, making sure I cut the potatoes safely as I could cut or injure myself and by making sure that I wear safety goggles just incase anything flies up which could injure or go in to my eye. I will also make sure that I put the bags and stools under the tables as somebody could fall over and get hurt.
I will make it a fair test by making sure that I keep the same temperature (constant), which is room temperature, as I will be working in a classroom because it will be a fair test because if I don’t and I work in a box for one concentration and in a room for another it wont be a fair test as I wont get good accurate results.
I will also make sure that the number of sugar solution that I use will be the same throughout the whole experiment for each concentration to make it a fair test because if I don’t, one concentration will have more solution and my will results will turn out inaccurate and it will not be a fair test. I will use 20ml of solution each time and I won’t change it because it wont be a fair test if I change it. I wont change the volume because it will affect my results and it wont be a fair test. And I will also try to use a range of concentrations.
I will avoid cross contamination by making sure that I use different equipment for each different solution and concentration and I will wash each equipment after each concentration, this will make my test fair and it wont affect my results but it’ll give me good accurate results, if I do cross contaminate then the solutions will be mixed and it give me inaccurate results which wont be a fair test.
I will make sure I use the same potato because if I use a different potato then it wont be a fair test because each potato is different and my results will be different therefore it wont be a fair test. I will make sure that I keep the same things about the potato like if I use the skin then I’ll have to use it all the time and I will also keep the same length, surface area and whether it is cooked or not, I will keep all these things the same to make it a fair test because if I don’t then It wont be a fair test because if I change all these like the length I will get different potatoes each time and it wont be a fair test.
I’ll make sure that I keep the potato in the solution for equal amounts of time, not change it for every different chip to make it a fair test. The time that I keep the potato in is really important because it shows my results which will be a fair test if I keep it in equal amounts of time because if I keep it for longer then it will delay my time which will affect my results giving me inaccurate and unfair results.
I will do this experiment twice to make it fairer and to compare my results to get an average.
I will measure the length in 0.1mm to get good accurate results; I will also measure the mass accurately by using 2 decimal places to get fairer and better and accurate results. The equipment which I will measure the potato is a ruler, a cork borer this is because it cuts and measures more accurately which will give me accurate results for the size of the chips.
PREDICTION
I predict that each that each time the concentration increases the mass of the potato will decrease, because the particles of a concentrated solution are high therefore will make more potato decrease in mass.
Quantative prediction
I think that doubling the concentration of solution will half the mass of the potato lost because the more concentration solution will allow water to pass from the potato cells back into the beaker. Making the chips lighter. As water molecules move from high concentration to low concentration. Also osmosis is movement of water molecules from an area of low concentration through a permeable membrane.
E.g. 1.0m=3g
2.0m=1.5g
1.0m 2.0m
3g 1.5g
I think the point of equilibrium will also be reached, as after a while I don’t think the potato will change any more.
The plasmolysis (the point where it can no longer change) will be reached when no further change occurs.
I have predicted this because each time the sugar solution increase, there are more sugar molecules than so it decrease the amount of potato even more, this is because the molecules are stronger therefore have the power to decrease more potato.
METHOD
The equipment that I will use is: -
Safety goggles
1 white potato
Scalpel
Petri dish
7 different sugar solutions
Distilled water
Test tube rack
Test tube
Ruler
Electronic scale
Stopwatch
-The first thing I did was to collect all my equipment and washed it to avoid cross contamination
-I then put on my goggles to make it a safe test just incase anything flew into my eyes.
-Then I had to set my equipment up (7 test tubes) and cut up the potatoes into 7 chips (I used a white potato) equally to make it a fair test using the cork borer.
-I also had to put the different concentrations in the test tubes, but I measured 20ml first before I put it in to make it a fair test which were; distilled water, 0,2m, 0.4m, 0.6m, 0.8m, 1.0m, 2.0m.
-The next thing I did was measure and weighed the potatoes and record it down in my book and put the potatoes in the test tubes in each concentration. The mass of the potato at the start was 1.53g.
-I started the stopwatch when I put the potato in the test tube to make it a fair test and to get good accurate results, this us because if I didn’t start the stopwatch when I put the potatoes in timing would’ve been wrong which would’ve affected my results.
-I timed it for 30 minutes and I took each of the potato out and measured and weight it and recorded it down.
-I washed all the equipment and put all the equipment away and I threw the potatoes away in the bin.
-I then repeated all this again to make it a fair test and to get an average.
RESULTS
On the next page it shows the line graph, which I have drawn, which shows the average change in mass.
CONCLUSION
My results show that an increase in the sugar solution has a change in the mass of the potato. The mass increases as you go into the positive area of the graph (from distilled-0.4M) this is showing that the molars, which are increasing, are moving from high water concentration to low concentration as we go into the negative area of the graph it shows that it is going down. The concentration of the cell sap is at the point of about 0.6Molar. This is all happening because there are less water molecules and the sugar molecules are increasing so it is becoming stronger, because the water molecules are moving out because the potato is getting less because of osmosis (diffusion of fluid through a partition into another fluid, movement of water molecules from an area of low sugar concentration through a permeable membrane).
My results tell me about my prediction that each time concentration goes up it will reduce the mass of the potato, which is what I said so my prediction was right. My prediction was right because what I said actually happened and my results tell me this because each time the concentration increases the mass of the potato decreases because the water molecules are moving out of the cells so it is stronger each concentration you go up, but it did not half the mass if the concentration was doubled so my quantative prediction was wrong. The outside of the potato was isotonic in the 0.4-0.6 concentrations. The mass of the potato decreased between 0.55 onwards. The point of equilibrium was reached between 0.4 and 0.5m so I have to look at carefully to find the actual one: 0.4, 0.45, 0.47,0.5 0.55, 0.57, 0.6. And the potato has taken in more water, meaning that it is heavier in solutions which are dilute like 0.1M, 0.2M, potatoes have also lost water in concentration solutions of 1.0M and 2.0M.
My quantative prediction was not exactly correct because I said that halving the concentration will double the mass which isn’t what happened because I said that
1.0M=3g
2.0M=1.5g
But the actual results were
1.0=1.99g 1.99g =1.03g
2.0=1.93g 1.93
So it isn’t doubled so I am wrong, I proved my quantative prediction by taking the information from the graph and comparing it to my quantative prediction and seeing if I am right, because I am not right. Because this shows that it isn’t doubled like I said. I also drew a best-fit line to get a better way of my graph.
EVALUATION
To make my results more accurate and better I could’ve used a larger variety of sugar concentrations because there would’ve been a larger range to analyze and I could’ve used up to 4m instead of 2m, also by being more precise near the point of plasmolysis. And by incubating the potato for a longer time because although we only had 2 lessons to do this experiment I would’ve put it in for longer in the sugar solution and I would’ve had more chance of a better reaction which would’ve improved my results, I could’ve also done this by measuring the potato every 20mins and leave it in for 24hours instead of 1 lesson (30mins) this way I would find out when the potato stops changing (isotonic). I could’ve looked at the temperature carefully to make it a fair test as it affected the rate of osmosis, by making sure it is the same because it could change as the water could be moving fast so it would be warmer or the water could be still so it would be colder, and I could be doing it on a radiator or near a window, which would affect my results because it would be warmer near a radiator or colder near a window, and because things like body heat and draughts would also affect my experiment. I could’ve solved this by doing the experiment in a beaker filled with water of the same temperature. I could’ve also improved the quality of the potato by making sure the cells aren’t damaged because moving the potato could move the cells because I could drop the potato on the floor, I could solve this by making sure the potato is o.k. And all the same because it’ll affect my reaction. And also the technicians could’ve measured the concentrations inaccurately.
The point where it crosses the line in the graph, which is its equilibrium, is 0.4-0.5m I showed this so that I could use the concentrations around that point to find the actual point. I had some anomalous results especially the 1m because it doesn’t fit the pattern, this could’ve happened because I could’ve maybe misread the scale.
As an extension I could’ve looked at the temperature or I could’ve looked at different types of potatoes or vegetables, and recorded the results like I did with this.
BIBLIOGRAPHY
I used a science book a CD Rom disk and the Internet to get information about osmosis.
The book that I used was “Science for you” by Graham Hill.
The CD that I used was Encarta 99.
The website that I used was
My science book (class notes)