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physics momentim questions

Free essay example:

  1.  Two billiard balls each of mass 80gm moving in opposite directions with a speed of 36km/hr collide and rebound with the same velocity. Find the change in momentum imparted to each ball due to each other?

Solution :

                                 Change in momentum image00.pngimage00.png

                                =mv- (-mv)

                                =2mv    

                                =2image00.pngimage00.png80image00.pngimage00.png10ˉ³image00.pngimage00.png10

                                =1600image00.pngimage00.png10ˉ³

                                =1.6kgm/sec

  1. A ball of mass 200gm falls from a height of 5m and rebounds to a height 1.25m.Find the change in momentum and the average force between the ball and the ground if the time during which they are in contact is 0.2sec? g=10m/sec².

Solution :

           Velocity on striking the ground, V=√(2gh)

                                                               =√(2image00.pngimage00.png10image00.pngimage00.png5)

                                                               =10m/sec

                      Velocity of rebounding V´=√(2gh´)

                                                               =√(2image00.pngimage00.png10image00.pngimage00.png1.25)

                                                              =5m/sec

                            Change in momentum =mv- (-mv´)

                                                              =mv+mv´

                                                              =m(v+v´)

                                                              =((200image00.pngimage00.png10ˉ³)image00.pngimage00.png (10+5))

                                                              =(0.2image00.pngimage00.png15)

                                                              =3kgm/sec

                                         Force image00.pngimage00.png time = 3kgm/sec

                                             F image00.pngimage00.png0.2 sec= 3kg/sec

                                                      So F = image01.pngimage01.png

                                                             F= 15N

  1. A cricket ball of mass 150g moving with a speed 12m/s is hit by bat so that the ball is turned back with a velocity 20m/sec. Calculate  the change in momentum and force applied by the bat if the ball is in contact with the bat for a time of 1image00.pngimage00.png10ˉ²sec ?

Solution :

                              Change in momentum =mv- mu

                                                               =m(v-u)

                                                               =((150image00.pngimage00.png10ˉ³)image00.pngimage00.png (-20-12))

                                                               =-4.8kgm/sec

                                          Force image00.pngimage00.png time =-4.8kgm/sec

                                                            F = image02.pngimage02.png

                                                               = -image03.pngimage03.png

                                                               = -4.8image00.pngimage00.png10² N

  1. A ball of mass 0.2kg moves with a velocity 20m/sec is brought to rest by a player in 0.1sec.find the change in momentum and the average force applied to bring the ball to rest ?

Solution :

                             Change in momentum =mv- mu

                                                               =m(v-u)

                                                               =(0.2image00.pngimage00.png (0-20))

                                                               =4.0kgm/sec

                                                            F = 4.0/0.1sec

                                                               = 40 N

  1. A body falls from a height of 100cm and rebounds to a height 50cm.Then change in momentum is 0.3788Ns.If the force exerted by the body on the ground is 3.78N find the mass of the body and the time of contact of it with the ground ?  

Solution :

 Velocity on striking the ground , V1=√(2gh´)

                                                        =√(2image00.pngimage00.png9.8image00.pngimage00.png1)

                                                        =4.427m/sec

           Velocity of rebounding , V2 = √(2gh´´)

                                                        =√(2image00.pngimage00.png9.8image00.pngimage00.png (50image00.pngimage00.png10ˉ²))

                                                        =3.13m/sec

                                 Change in momentum=  mv- mu

                                                                  =m(v-u)

                                                                  =m(v- (-u))

                                                                  =m(v+u)

                                                    0.3778  =m(4.427+3.13)

                                                               m=  0.050kg

                                             Force image00.pngimage00.png time =0.3778  kgm/sec

                                                              T = 0.3788/3.78

                                                               T=0.100 sec

  1. A  batsman hits back a ball straight in  direction of the bowler without changing the initial speed of 12m/sec. If the change in momentum imparted to the ball is 3.6Ns from batsman to bowler find the mass of the ball  if the ball is in contact with the ball for 0.2sec .  find the force exerted by the batsman?

Solution :

                                    Change in momentum =m(v- u)

                                                                3.6 = -24m

                                                                   m= 3.6/24

                                                                   m= 0.15kg

                                                  Force image00.pngimage00.png time = Change in momentum

                                                        Fimage00.pngimage00.png0.2sec = 3.6

                                                                    F = 3.6/0.2

                                                                       =18 N

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