Potato and Osmosis Investigation.

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Lewis Janes 11a                        

                                                     

Potato and Osmosis Investigation

General Introduction

I am trying to discover how osmosis is carried out and how it is affected by different concentrations of sugar solution. The key factor I plan to investigate is sucrose concentration, I will vary the sucrose concentration and calculate the effects of this factor on osmosis in the potato chips by recording the mass before the chip is placed in the solution, the mass after and the difference between them. I will finally calculate the percentage change and the required averages. In this experiment a potato will be cut to certain lengths (2cm), measured and placed into a sugar solution over a period of 48 hours. They will then be measured again to see if osmosis has occurred. (The potato chips will be covered in 30cc of solution to ensure that every one is completely covered).

Apart from the concentration of 0.0mol/litre the solutions have been made up before hand. The different solutions being used are:

        0.0M (Molar concentration)

        0.2M

        0.4M

        0.6M

        0.8M

        1.0M

There was some previous work that influenced my planning this was absorption. Absorption is the taking up of one substance by another, such as a liquid by a solid or a gas by a liquid (ammonia by water).

Prediction

Osmosis is defined as ‘the movement of water molecules from an area of high water concentration to an area of low water concentration, across a semi-permeable membrane’ (Encarta)

In a high concentration of water the amount of solute (e.g. sugar) is low. This could be called a weak or dilute solution. In a low concentration of water the amount of solute (e.g. sugar) is high. This could be called a strong or concentrated solution. I think that when two such solutions, are divided by a semi-permeable membrane, the water will move from the area of high concentration to the area of low concentration, until both sides are equal (have reached equilibrium).

This can be seen in living cells. The cell membrane in cells is semi-permeable and the vacuole contains a sugar/salt solution. So when a cell is placed in distilled water (high water concentration) water will move across the semi-permeable membrane into the cell (lower water concentration) by osmosis, making the cell swell. This cell is now referred to as turgid. When done with potato cells the cells would increase in length volume and mass because of the extra water.

Below is a diagram to describe Osmosis in plant cells:

In my experiment I believe that if these potato cells are placed in a solution with a high sugar concentration, then the opposite would happen. Water would move out of the cell into the solution. In extreme cases the cell membrane breaks away from the cell wall and the cell is referred to as plasmolysed.

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The potato cells will have decreased in length, volume and mass. The greater the concentration of water in the external solution the greater the amount of water that enters the cell by osmosis. The smaller the concentration of water in the external solution the greater the amount of water that leaves the cell.

However, I think, there will be a point where the concentrations of water inside and outside the potato cells are equal (isotonic). At this point there will be no change in the length, volume and mass of the potato, as the net movement of water ...

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