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Presented with raw potato how would you carry out an experiment to determine the concentration of the potato cell in molar strength?

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Introduction

��ࡱ�>�� 02����/�������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������������5@ ��0Y!bjbj�2�2 (,�X�X��������������������8" .�vVVVVVVVV�������$�R����VVVVV���VV�```V�V�V�`V�``r��rVJ �y3����Vr��0ra V a r�$�����a �r VV`VVVVV��`Presented with raw potato how would you carry out an experiment to determine the concentration of the potato cell in molar strength? The experiment was set up to be as fair as possible. Then the potato chips were cut into 15 cylinders using a cork cutter and then cut to a length of exactly 4cm each with a scalpel. Then three were weighed at one time on a top pan balance to find an average mass, this was done because it did not involve confusion over which potato cylinder was which after the experiment. Once these averages were found and recorded the potato chips were placed into their test tube solutions of 0.0M(distilled water), 0.25M, 0.5M, 0.75M and 1.0M solutions of sucrose. Then the contents, each containing three potato cylinders were left for 50minutes. When the time was over I removed the potato with a pair tweezers and placed them on a paper towel to try and dry of any excess water. Then I weighed the potato again together in their threes on a top pan balance and found the average mass. Prediction I believe from my past knowledge of a similar experiment involving raw eggs that the potato cylinders placed in the distilled water will be hyperosmotic, therefore the water will diffuse by osmosis into the potato from an area of high concentration down the concentration gradient. ...read more.

Middle

The graph shows that the potato in the 0.0M solution and in the 0.25M is hyperosmotic, as I said in my prediction, this means that there is a higher water potential in the distilled water and 0.25M solution than in the potato, which has a high concentration of solutes. Therefore this is why the water diffuses by osmosis down the concentration gradient from high concentration to low concentration, resulting in the potato gaining mass. The opposite occurs in the solutions where the molarity is higher 0.5M, 0.75M and 1.0M, the potato in these is hypo-osmotic because there is a higher concentration of water inside the potato than in the solutions, therefore the water diffused out of the potatoes by osmosis, down the concentration gradient and into the solutions outside, this resulted in the loss of mass. Another important fact is that the graph makes a shape that will result in the potato not being able to take in any more water or lose any more. Like I said in my prediction the cell wall causes the pressure that prevents this from happening, therefore the cell will never become iso-osmotic like an egg. On my graph I have marked the point where the graph line crosses the place on the axis where the potato neither loses mass nor gains mass. ...read more.

Conclusion

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