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# Presented with raw potato how would you carry out an experiment to determine the concentration of the potato cell in molar strength?

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Introduction

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Middle

The graph shows that the potato in the 0.0M solution and in the 0.25M is hyperosmotic, as I said in my prediction, this means that there is a higher water potential in the distilled water and 0.25M solution than in the potato, which has a high concentration of solutes. Therefore this is why the water diffuses by osmosis down the concentration gradient from high concentration to low concentration, resulting in the potato gaining mass. The opposite occurs in the solutions where the molarity is higher 0.5M, 0.75M and 1.0M, the potato in these is hypo-osmotic because there is a higher concentration of water inside the potato than in the solutions, therefore the water diffused out of the potatoes by osmosis, down the concentration gradient and into the solutions outside, this resulted in the loss of mass. Another important fact is that the graph makes a shape that will result in the potato not being able to take in any more water or lose any more. Like I said in my prediction the cell wall causes the pressure that prevents this from happening, therefore the cell will never become iso-osmotic like an egg. On my graph I have marked the point where the graph line crosses the place on the axis where the potato neither loses mass nor gains mass. ...read more.

Conclusion

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