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The Decomposition of hydrogen peroxide by catalyse

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The Decomposition of hydrogen peroxide by catalyse Aim To find out how the concentration of the hydrogen peroxide affects the rate of reaction between some potato and hydrogen peroxide. The equation for my reaction is 2H2O2=2H2O+O2 I am using potato because it has plenty of catalyse, an enzyme found in all living cells. Enzymes increase the rate of reaction without being consumed in the process. To react with the potato hydrogen peroxide in varied concentrations. I am using it because the enzymes react well at its Ph level. Variables Temperature Mass of potato Surface area of potato Concentration of H2O2 Volume of H2O2 Type of potato Prediction I predict that as the concentration of hydrogen peroxide goes up, the amount of gas collected will be proportional. I will be changing the concentration of Hydrogen peroxide.I think this because with a higher concentration, there will be more H2O2 molecules so there is a greater chance of collision. Catalyse makes H2O2 decompose into H2O and O2. ...read more.


I will then record how much gas is collected. To increase the accuracy of my results I will be doing them all on the same day so the room temperature is constant. I will also be repeating the tests three times and taking an average. This will ensure my results to be as accurate as possible. I plan to use low concentrations first and (0.1) and ascend to using higher concentrations (1.0) I will repeat the experiment three times to make sure it is accurate. Diagram Equipment list Water bath (washing up bowl) Measuring cylinder Conical flask Stopwatch Cork with delivery tube Potato Different concentrations of hydrogen peroxide Pestle and Mortar To ensure safety I will make sure I will wear goggles so my eyes are protected and mop up any spillages properly. I will tuck the chairs in and stand up. I will clear the area so nothing is damaged. Observations Concentration Gas collected cm3 Averages 0.1 1.0 cm3 Concentration Gas collected 0.2 1.25 cm3 0.1 1 cm3 0.4 2.0 cm3 0.2 1.3 cm3 0.6 2.5 cm3 0.4 ...read more.


So, when the concentration was 0.4m the average amount of gas collected was 2.08cm3. This proves my prediction to be correct. Evaluation The experiment went well apart from one anomalous result. I think this can only have occurred due to the fact that we could not use 0.8M H202. This meant there was a gap of 2M between concentrations. This affects the correlation of the graph. As the same jump occurred in all three of my experiments I have no reason to believe it was a mistake of mine. I think my results are accurate because I took the necessary precautions to ensure the test would be fair and safe. If I were to make an improvement on my method it would be to use cubes of potato not mash it because mashing it means there would be a slightly different surface area in each test. This could have affected the results. I would also have used a better range of concentrations to prove that the results continue proportionally. I think if I had a larger range of concentrations, my results would be improved because my line of best fit would become more precise. ...read more.

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