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The Effect of Catalase Concentration on the Rate of Hydrogen Peroxide Decomposition

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Bio coursework Tim Jones 10N The Effect of Catalase Concentration on the Rate of Hydrogen Peroxide Decomposition Plan Background Information: An enzyme is a biological catalyst. They speed up the rate of a reaction however they are not used up. Enzymes are made to be specific, this means that they can only have one substrate that they will work on. Each enzyme has an active site that is where their own specific substrate will fit. Enzymes all work best at a temperature of 37C, roughly body temperature, when the temperature gets to about 40C the enzyme cannot take all the vibration and movement and breaks apart, therefore no longer works on the substrate as the active site has changed shape. Most reactions work better at higher temperatures, this is because molecules move around much quicker. This makes the molecules have more chance to collide with the substrate. With more collisions there is more chance of a reaction-taking place. This is called the 'collision theory'. The collision theory also works on the concentration of enzyme and substrate; the more enzymes are put in the quicker the substrate will be broken down, because the enzymes and substrate would collide more often. At a certain concentration however the Hydrogen Peroxide molecules run out and so no matter how many enzymes are put in they cannot work when there is no substrate left to work on. ...read more.


In theory if I carried on increasing the volume of potato then it would plateau. Bio coursework Tim Jones 10N Results Experiment 1 (graph 1) time 1g potato 2g 3g 4g 5g 10 0cm3 02 0cm3 02 0cm3 02 0cm3 02 5cm3 02 20 0cm3 02 0cm3 02 4cm3 02 2cm3 02 10cm3 02 30 0.5cm3 02 1.5cm3 02 6.5cm3 02 6cm3 02 15cm3 02 40 1.3cm3 02 2.5cm3 02 9cm3 02 9 cm3 025 20cm3 02 50 1.9cm3 02 3.6cm3 02 13cm3 02 13cm3 02 25cm3 02 60 2.5cm3 02 5cm3 02 15.5cm3 02 17cm3 02 29cm3 02 70 5.1cm3 02 5.9cm3 02 18cm3 02 20.5cm3 02 30.4cm3 02 80 3.5cm3 02 7cm3 02 20.1cm3 02 23.8cm3 02 37cm3 02 90 4.3cm3 02 8cm3 02 22.5cm3 02 26.5cm3 02 40cm3 02 100 4.5cm3 02 8.9cm3 02 24.5cm3 02 29.5cm3 02 45cm3 02 110 5.5cm3 02 10cm3 02 24.7cm3 02 32cm3 02 47cm3 02 120 5.9cm3 02 11cm3 02 27 cm3 02 34.2cm3 02 50cm3 02 Experiment 2 time 1g potato 2g 3g 4g 5g 10 0cm3 02 0cm3 02 1cm3 02 0 cm302 4cm3 02 20 0cm3 02 1cm3 02 4cm3 02 1.6cm3 02 9.8cm3 02 30 2cm3 02 1.5cm3 02 6.8cm3 02 5.9cm3 02 16.6cm3 02 40 3cm3 02 2.5cm3 02 9.8cm3 02 9.8cm3 02 21.2cm3 02 50 4cm3 02 4cm3 02 12cm3 02 12cm3 02 28cm3 02 60 5cm3 02 5.1cm3 02 14.5cm3 ...read more.


The concentration of substrate was measured carefully each time in the same measuring cylinder; 5ml Hydrogen Peroxide, 15ml Water, so I do not believe it was the concentration that caused more 02 to be produced. The time was taken with the same stop watch throughout the experiment and each volume was taken every ten seconds for a period of exactly two minutes, so I also do not think it was the time that caused the rise in results. I believe that the only ting that could have caused such a clear rise in 02 produced was a rise in temperature, within the Hyrdrogen Peroxide. I found out that the Hydrogen Peroxide was kept in the fridge, but during the experiment it was kept in the laboratory and so would have heated up gradually. The rise in temperature would cause the Hydrogen Peroxide molecules to heat up. When the molecules heat up, they gain more energy, therefore moving faster, which would cause more collisions between the active sites and substrate, causing the reaction to happen faster. This would explain why the second set of results produced more 02 than the first. If I did the experiment again I would let the Hydrogen Peroxide heat up to room temperature before I started and moniter the temperature regularly. All in all however even though the two sets of results were different they followed the same pattern that the more Catalase added the faster the rate of reaction, the more 02 produced in the time given. ...read more.

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