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The Effect of Catalase in the Breakdown of Hydrogen Peroxide

Extracts from this document...

Introduction

The Effect of Catalase in the Breakdown of Hydrogen Peroxide Aim: to give a detailed explanation on enzyme/ catalysts and an experiment to further illustrate my given hypothesis. To explain the effect of catalase as hydrogen peroxide decomposes. In addition; I must investigate Hypothesis: When catalase is the addition to an experiment, the reaction (depending on the volume of the concentration) would be a fast one. If this catalase is reacted with hydrogen peroxide, it would provide energy to produce oxygen and water. By measuring the level of the speed of the reaction, one can determine the volume of oxygen produced. The higher the oxygen amount; the faster the reaction had occurred. As the concentration is decreased, it means that the rate of the reaction would decrease. For this, I predict the higher the amount of catalase concentration added to the solution, against the substrate, the faster the rate of reaction. I also predict; as more catalase is added, more collisions occur in which more enzymes have available active sites. This is for the same reason that the higher the concentration; the quicker the rate of reaction. On the other hand; less concentration can slow down a reaction. This is due to fewer enzymes available for a reaction. In addition; I hypothesis: when more active sites are present, more hydrogen peroxide particles can bind specifically to them. Therefore; when the hydrogen peroxide particles break down faster, more oxygen and water can be released. Thus; a faster reaction can take place. The problem that I am investigating is if the percentage of catalase that I will select will have any effect on the hydrogen peroxide as it decomposes. I want to test a theory that looks at ways in which the rate of the reaction can be manipulate the results and the catalase amount used. Introduction: Enzymes work in particular ways. Enzymes are proteins that affect the rate of a reaction as it speeds up the process and as proteins they have tertiary structures (shaped with amino acids). ...read more.

Middle

If this is so then the results are wrong and so the graph would also be affected. Concentration of hydrogen peroxide This amount should always stay constant (5ml) as the aim of this experiment is to see the rate of the reaction in which the enzymes would bind to the substrates. Depending on how much is put in, more than 5ml can increase the rate of the reaction. On the other hand; les than that can decrease the rate. Concentration of catalase This is will not stay constant. This is because another aim in this investigation is to test the rate of reaction when the concentration of the catalase is manipulated. This experiment will test the best concentration of catalase to produce a large volume of oxygen, as well as testing which concentration will allow a fast rate of reaction. Though this concentration amount is not constant, it should still stay under the 10ml limit. Method: I have used the same method from the preliminary as it best suited my working out. However; in addition have also repeated the experiment for fair testing and to get the best average results possible in this reaction. 1. Dice an unpeeled potato, into small slices (the bigger the surface area, the better), then put into a blender to liquefy. 2. Pour into beaker to then divide into four test tubes. 3. Place test tubes into centrifuge and wait till the unpeeled potato has separated into a thick layer (top layer) and a more liquid layer (bottom layer). 4. Place test tubes in a safe place as you will come back to use it. 5. Fill a small bath tub with water, mid-length. 6. Fill a burette with water - preferably near the 50cm3. Then place a stand over the tub, this will hold the burette into place during the whole experiment, so make sure it is straight so that reading the measurements constantly is accurate. ...read more.

Conclusion

The experimental reaction in all the percentages of the catalase should occur during a room temperature environment. This is because, this is the normal and best temperature that the enzymes work best at without denaturing or having minimum effect on the whole reaction. However; there might have been another reason why the rate of the reaction was fast due high percentage of concentrated catalase, as it could have been in the influence of the temperature. I also think that the depth the of the water in bath tub should also be constant as when the burette in put into the tub, the water surrounding adds pressure, which can affect the speed in which the gas particles reach the surface of the burette. When beginning the reaction, the bung should be put on top of the conical flask immediately so that the gas particles can be collected in the burette. This can prove tricky to do because at the same time, the stop watch should be activated. To solve this problem, it is best if another person assists in pressing the button on the stop watch while you close the top of he conical flask quickly. This can lead to the error and lead to unfair and inaccurate results. This can also suggests that the results do not show the precise measurement recorded. It means that the reaction was in fact running for more than the time limit of 2mins. Finally; I were given another opportunity to rewrite my method, I would want to test a theory in which I would change the concentration of the hydrogen peroxide instead of the catalase. This is so that I can watch the reaction occur according to the results that I have achieved in this current experiment. This can either back up my current experiment or can alter my hypothesis in such a way that can also change my results. With this hypothetical experiment I can observe how an increase of the hydrogen peroxide could have in effect on the constant concentration of catalase. ...read more.

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