The effect of concentration in the rate of enzyme catalysed reaction

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Amanda Gaber

March 2006

The effect of concentration in the rate of enzyme catalysed reaction

Aim: To investigate how altering the concentration of the substrate, hydrogen peroxide, affects the rate of a catalytic reaction.  

Hydrogen peroxide (H202) is a toxin, which is a by-product of metabolism, namely anaerobic respiration.  Hydrogen peroxide (H202) is a colorless and transparent liquid, which is relatively stable and so requires the presence of catalase in order to decompose during anaerobic respiration.  It is a poisonous toxin and must be broken down into harmless by-products in order to be removed from the organism’s body.  Catalase is one of the fastest acting enzymes in an organism’s body.  It catalyses hydrogen peroxide, producing water and oxygen.  A single molecule of the globular protein decomposes 40,000 molecules of H202 per second.  The catalase is responsible for producing 1012 molecules of oxygen per second. For this experiment, I am going to use yeast as the catalase.

The reaction between hydrogen peroxide and catalase is illustrated in the equation below;

Predictions:  I predict that as the concentration of the hydrogen peroxide increases, there will be a greater number of collisions between the substrate, hydrogen peroxide, and the enzyme catalase.  Because of the collision theory, where there is an increased probability of molecules colliding as the concentration of molecules increases, I predict in increased rate with increased substrate concentration.  However, I am going to keep the enzyme concentration the same for all conditions so I anticipate that there will be a saturation point, where all of the enzyme active sites will be in use by substrates or products, and so there will be a point where the rate of reaction will plateau out.  For lower concentrations of the hydrogen peroxide, I predict that the rate of reaction will be directly proportional to the concentration of hydrogen peroxide in each solution. If I double the concentration of the hydrogen peroxide, there will be twice as much volume of solution.  Furthermore, if I half the concentration of the hydrogen peroxide, I expect to see half the volume of solution. For example, if I saw 50ml with a concentration of 2M, if I altered this to 1M, I would expect to see in the region of 25ml of solution.

The variables that could affect the rate of reaction for this experiment are concentration, temperature, pH, or pressure.  For the purpose of this investigation, I am going to alter the concentration of the substrate, Hydrogen peroxide so this is the independent variable.  I am going measure the volume of solution after a 25 second interval, as a result of the decomposition of the hydrogen peroxide to water and oxygen (dependent variable).  In order to ensure that this is a fair investigation, all other variables need to be controlled.  Temperature will be maintained at 35°C using a water bath, and the pH will be kept the same, using a buffer, which in this instance is the washing up liquid.  Furthermore, the solution will be kept in controlled conditions by placing a stopper on top of the test tubes so that none of the solution or resultant oxygen escapes.

I will vary the concentration of the hydrogen peroxide as follows:

  • 100% H202 – 2ml yeast and 1 ml washing up liquid
  • 80% H202 – 2ml yeast and 1 ml washing up liquid
  • 60% H202 – 2ml yeast and 1 ml washing up liquid
  • 40% H202 – 2ml yeast and 1 ml washing up liquid
  • 20% H202 – 2ml yeast and 1 ml washing up liquid
  • 0% H202 – 2ml yeast and 1 ml washing up liquid

I will always use 2ml of hydrogen peroxide, regardless of the concentration.

I am going to measure the volume of the solution 25 seconds after mixing the hydrogen peroxide, yeast and washing up liquid together.  I am going to repeat this experiment three times for each concentration of hydrogen peroxide in order to obtain an average reading.  I will then be able to plot a graph of concentration against volume in order to ascertain what the rate of reaction is.

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I need to find out what the areas of error fall into.  Firstly, the measuring cylinder is only accurate to within +/- 1cm3.  Also, the volume readings will be measured at the bottom of the meniscus at eye level.  

Background Knowledge

As a general rule, the rates of chemical reactions increase with increasing concentration.  This is due to a number of reasons, namely because there are more molecules in a higher concentrated solution, meaning that there is an increased kinetic energy. This in turn means that there will be more collisions between molecules.  When there is a ...

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