The effect of concentration on the rate of reaction of calcium carbonate.

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The effect of concentration on the rate of reaction of calcium carbonate

        Aim: My aim is find out what effect would hydrochloric acid (the reactor) have on calcium carbonate (the reactant).

        Prediction:  The higher concentration of acid, the faster rate of reaction with calcium carbonate. My reasoning for this, is that the more acid particles in the acidic solution there are, the more particles will collide with the calcium carbonate particles, and the more collisions there are, the quicker pace of rate gets. In essence, I predict my results would be, the concentration being directly proportional to the length of time. My prediction is based on collision theory (*=explained later on).

Equipment: the equipment I will need for this experiment is:

  • Flask
  • Cork
  • Delivery tube
  • Trough
  • Measurement tube     2
  • Timer
  • Pipette
  • Spatula
  • Apparatus stand
  • Balance

Method: as you can see on the previous page how everything is set out. I will be explaining the method in stages:

  1. Firstly, I will fill the measuring tube up with water and the same with the large trough. I will then place the tube into the trough without spilling the water, and use an apparatus stand to hold it upside down.
  2. After which, I will get another measuring tube pour 20cm3 of the acidic solution into it using a pipette, and then pour that into the flask. Simultaneously, I will put 4 grams (weighed) into the flask, put the cork on and start the timer.
  3. At an interval of every 5 seconds for 40 seconds I will be checking hoe much the water has decreased in the measurement tube, telling me how much the gas has increased. Later, recording the results.
  4. I will do five different experiments in total, all with different concentrations, and each will be repeated twice to get an accurate average.

Explanation: what happens is when both hydrogen and calcium carbonate react they release a by-product-carbon dioxide. So, when there is no more of this gas left the reaction has taken place. I am trying to find out the initial rate of each concentration. So measuring how much gas is given off cm3/s, is telling me what I need to know. Anyway, as they both react, the carbon dioxide travels up and into the delivery tube. It is then led into the measurement tube full of water. The gas rises up and then as more gas comes in; the pressure becomes greater, therefore pushing the water out. That’s how I measure the rate.

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Variable/s: the ideas I came up with for the variable factor were: the quantity of either the acid or calcium carbonate, the temperature  C, density or environment of which the calcium carbonate came from.. of course not all of these were practical, and as a class we decided that the concentration would be the variable. Concentrations we had to work out but the other three were given to us. Here are the concentrations given in table format:

As you can see the two-I bullet pointed are the concentrations I had to figure out and use to make the ...

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