The effects of electrolysis of Copper Sulphate Solution and copper electrodes

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Rory Franklin Chemistry Coursework 03/07/2001

10ABC Planning

Aim:

We are investigating the effects of electrolysis of Copper Sulphate Solution and copper electrodes, and the effects of changing the voltage of the current flowing through the circuit. We are keeping the concentration and the temperature constant.

Background Information:

I know from my own knowledge that electrolysis is the breakdown of a substance by electricity. I also know that opposite charges attract, this means that positive ions are attracted to the Cathode (-ve) and negative ions are attracted to the Anode (+ve). I know from the preliminary experiment that we did, that the Anode LOSES mass, whilst the Cathode GAINS mass. This is because the positive ions from the Anode are attracted to the Cathode through the Copper Sulphate solution and this means that the Cathode gains weight and the Anode loses weight.

The equation at the Cathode is: Cu²+ + 2e¯ Cu

The equation at the Anode is : Cu - 2e¯ Cu²+

Faraday's Law: Michael Faraday did lots of the early work on electrolysis, and we know because of his work that it takes 96500 coulombs to deposit one mole of a metal with a single charge. This is called Faraday's Law. So, because copper has a charge of 1+, we know that it takes a charge of 96500 coulombs to deposit just 1 mole of copper. The equation fro the charge is:
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Charge = Current X Time

(In Coulombs) (In Amps) (In Seconds)

PREDICTION:

I predict that the Anode will lose mass and the Cathode will gain mass. I also think that the amount of weight lost at the Anode, will equal the amount of weight gained at the Cathode. I predict that as the voltage increases, the weight loss/gain will increase. I know this from my own knowledge that opposite charges attract and the copper atoms from the Anode lose 2 electrons and enter the solution as Cu²+ ions. Because these are +ve ions, they will ...

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