• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

The Problem that I am going to investigate is to see the amount of energy required to raise the temperature of a one kilogram object by one degree Celsius. I will measure the temperature of the object every sixty seconds.

Extracts from this document...

Introduction

Physics Coursework

The Problem that I am going to investigate is to see the amount of energy required to raise the temperature of a one kilogram object by one degree Celsius. I will measure the temperature of the object every sixty seconds. I will do this for ten minutes (six hundred seconds).

Some scientific knowledge that may help me in this investigation is the different methods of heat transfer. The different methods of heat transfer are: conduction, convection, radiation and evaporation. All of these methods of heat transfer may occur during me experiment.

Here is a description of all the processes of heat transfer:

Conduction

This is where the heat energy transfers through surfaces/objects. The heat energy makes the particles of the object vibrate which make the particles next to it vibrate, which makes the next one vibrate, etc. Once the thermal energy has passed through all the particles, it gets released into the atmosphere. Materials that are good heat conductors tend to be good electrical conductors. Examples of these are: metals such as gold, silver and copper. Other materials such as glass have smaller heat transfer values and are poor at transferring heat.

Convection

This is frequently the most appropriate way to transfer heat efficiently.

...read more.

Middle

The variables are factors that I will change throughout the experiment. These variables are: The temperature rise and the mass of the object. The constant is something that is always the same throughout the whole experiment. The constant in my experiment is apparatus and the time that each material is heated for.

To prepare for the actual experiment, I carried out some preliminary work. This preliminary work was simply carrying out a ‘fake’ version of my experiment to see what changes need to be made to make it more accurate. As I carried out this preliminary experiment, I recorded the results down.

The starting temperature was 26.5°C.

I (a)

T (s)

V (v)

E (j)

Temperature (°C)

2.72

60

9.72

1586.3

27

2.72

120

9.72

3172.61

27

2.72

180

9.72

4758.91

27.5

2.72

240

9.72

6345.22

29

2.72

300

9.72

7931.52

29.5

2.72

360

9.72

9517.82

30.5

2.72

420

9.72

11104.1

32

2.72

480

9.72

12690.4

33

2.72

540

9.72

14276.7

34.5

2.72

600

9.72

15863

36

During this preliminary experiment, I used 12 volts. After carrying out the experiment, I realised that my procedure was incorrect as there was significant heat loss. The error that I made was that the 1kg block had a rather big hole, which had a much wider circumference than the immersion heater. This meant that there was a lot of heat loss as there was such a big gap between the two objects. For my final experiment I will make sure that the immersion heater fits exactly into the object to reduce any heat loss.

...read more.

Conclusion

If I did my experiment again, I would the main improvement that I would make is to use brand new equipment. This is because I used the equipment provided by the school, which was quite old and fairly used. This meant that there was a good chance that the results were recorded with faults. This may have been the case because some equipment may not have been doing there job accurately. For example, the schools immersion heater was quite old and had been used a lot before, this meant that the immersion heater may not have been emitting the correct amount of heat energy.

Looking at all the inaccurate equipment, leading to the potentially incorrect results, I think that my results are not accurate enough to draw firm conclusions. This is because one faulty piece of equipment can lead to an array of inaccurate results which could lead to erroneous conclusion, and the schools equipment being faulty is far too possible to be a reliable source of results.

Another experiment that could be carried out to extend the work that I have done is an electrical conductivity experiment. This experiment could analyse the relationship between the rate of electrical conductivity and the mass of an object; although, this experiment would need very accurate pieces of equipment.

By Usman Naeem

...read more.

This student written piece of work is one of many that can be found in our GCSE Electricity and Magnetism section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Electricity and Magnetism essays

  1. My aim is to measure the specific heat capacity of 4 metals and find ...

    * Last of all, check that the voltage is on twelve watts and turn the power and the stop clock on at the same time. Results! I am going to find out the specific heat capacity by using this formulae; C = Q M ?T That formula will work out the specific heat energy of the metal block.

  2. Measuring the specific heat capacity of water

    sphc, by subtracting the final temperature by the initial temperature, you only base your calculation of two sets of data. This is unreliable, because if one of them proves to be inaccurate, then this impacts the answer proportionally. The gradient method is more accurate, because you are taking the data

  1. Finding a material's specific heat capacity

    The voltmeter, ammeter, stop clock and temperature probes will be tested to ensure they work properly, are set to the correct settings and their displays will be labelled to be sure of quick and easy reading. * Oil will be put in the temperature probe and heater receptacles in the

  2. Investigation to see the relationship between actual and theoretical energy released when burning different ...

    C=O = 745 =1490 O-H = 464 =464 Total= 3346 kJ/mol 1 1/2 O=O = 497 =745.5 Total= 2806.5 kJ/mol Energy balance = 2806.5 - 3346 ?H= -539.5 kJ/mol As we go through the homologous series the amount of energy released increases as a lot more bonds are broken than

  1. Choosing a light source

    sun does not hit the solar panel The light atomically turns off and on. This means that when the light is needed, it is there with out having to turn it on. The light will not work as will in short days like in winter.

  2. Investigating The Heat Of Combustion Of Alcohols.

    Distance of copper calorimeter from the flame Length of time water is heated for Temperature change Key Variable: Alcohol used Method: The apparatus will be set up as shown in the diagram above. We must ensure that the boss and clamp are tightened properly to ensure that no apparatus is in danger of getting knocked over or falling.

  1. My aim is to investigate the rate of energy loss in different types of ...

    in my experiment, 70ml), and pour the cold water into my first chosen cup (e.g. the plain white polystyrene cup) and mark the water level on the inside of the cup with the pen. After that, I will empty the cup and with the heatproof mat and lid, I will

  2. In this investigation, I am going to investigate how increasing the temperature of substance ...

    This explains why liquids tend to have higher rates of specific heat capacity compared to solids because heat is transferred much quicker through conduction than convection. If you compare the specific heat capacity of copper, (390Jkg- K- ) to the specific heat capacity of water, (4180Jkg- K- )

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work