The purity of aminosulphonic acid

Authors Avatar

                                             The purity of aminosulphonic acid

Amount of acid used for each titration:

  1. 23.00-0.00=23.00 cm3
  2. 22.50-0.10=22.40 cm3
  3. 45.10-22.40=22.70 cm3
  4. 23.50-1.00=22.50 cm3

The amount of acid used for the first titration is a little higher than it should be so to make the calculation much more accuracy I will ignore the first one and I will work out the average of the other three values:

22.40+22.70+22.50=67.6 cm3

67.6/3=22.53 cm3 (2 decimals place)  

22.53 cm3 is average amount of acid (H2NSO3H) reacted with 25.00 cm3 of alkali (NaOH) with concentration of 0.200 moldm-3.

Join now!

Now I am going to work out the number of moles of NaOH in 25.00 cm3 of that with concentration of 0.200 moldm-3:

CV=M

C=0.200 moldm-3                 M=0.200*25.00/1000=0.005 number of moles of NaOH      

V=25.00 cm3                                                                        reacted with acid.

M=number of moles

 

As the ratio of the acid to the alkali ...

This is a preview of the whole essay