The The Molecular Formula of Succinic acid

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                                      The Molecular Formula of Succinic acid

Problem

‘Describe in detail how you would determine the relative formula mass of Succinic acid’

 

The relative formula mass is the mass of 1 molecule of succinic acid compared with 1/12th of the mass of an atom of carbon-12. This is obtained by adding together the relative atomic masses of the atoms within the molecule according to its written formula. However we do not know the exact formula:

                                           HOOC(CH  )nCOOH              Where n is a whole number

                                                                                             between 1 and 4

So to calculate the relative formula mass I must use the formula m = n ×Mr and rearrange it to make Mr the subject  Mr = m

                                            n

However I do not know the number of moles for a given mass. I can calculate this by preparing a standard solution of the acid and performing a titration experiment.

Firstly I would like to calculate a likely value of the relative formula mass given the information above.

    Suppose n = 3  then HOOC(CH  )  COOH and Mr = 1+(2 x 16)+12+(3x12)+(3x2)+12+(2x16)+1

                                                                                     = 132

To perform the titration I have chosen to use equal concentrations of acid and alkali at 0.1mols/dm³. This is a low concentration as the more concentrated the solution, the more rapidly the reaction takes place. This can be explained by the collision theory as increasing the concentration of the reactants increases the number of particles resulting in an increased number of collisions. If the reaction takes place too rapidly then it will be difficult to identify the exact point at which the alkali is neutralised and the results will become less accurate.

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To prepare my acid solution I must dissolve an accurately weighed amount of anhydrous succinic acid to 250cm³/0.25dm³ of water to achieve a concentration of 0.1mols/dm³. What mass of acid is required to achieve this concentration?

n = c × v which is 0.1 × 0.25 = 0.025 moles

The mass of 0.025 moles = n × Mr  which is 0.025 × 132 = 3.3g  

This is obviously not an accurate mass as I do not know the real Mr but this is an estimate so that the reaction occurs at a suitable rate.

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