• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month
  1. 1
  2. 2
  3. 3
  4. 4
  5. 5
  6. 6
  7. 7
  8. 8
  9. 9
  10. 10
  11. 11
  12. 12
  13. 13
  14. 14
  15. 15

The Use of Volumetric Flask, Burette and Pipette in Determining the Concentration of NaOH Solution

Extracts from this document...


UESB 1113 General Laboratory I Practical Component (II) : -Atomic Structures & Periodicity Group 6 / 2 Name: (1) Yeo Shi Wei (05UEB01783) Bachelor of Science (Hons) Biotechnology (2)Timothy Lee Tek Wang (05UEB02658) Bachelor of Science (Hons) Biotechnology Experiment No: TWO (2) Title: The Use Of Volumetric Flask, Burette and Pipette in Determining the Concentration of NaOH Solution. Date: 10 / 6 / 2005 Laboratory: SD017 Lecturer: Mr. Lee Chong Yong Experiment 2 Title: The Use of Volumetric Flask, Burette and Pipette in Determining the Concentration of NaOH Solution Objectives: - To carry out acid-base titration and determine the end point with the use of indicators such as phenolphthalein. - To get the concentration of base when the concentration of acid is known. - To do calculations related to titration. Theory & Background: Titrations are used to determine the concentration of acids or bases in solution. For example, a given volume of a solution of unknown acidity may be titrated with a base of known concentration until complete neutralization has occurred. This point is called the equivalence point and is generally determined by observing a color change in an added indicator such as phenolphthalein. From the volume and concentration of added base and the volume of acid solution, the unknown concentration of the solution before titration can be determined. Titrations can also be used to determine the number of acidic or basic groups in an unknown compound. A specific weight of the compound is titrated with a known concentration of acid or base until the equivalence point has been reached. From the volume and concentration of added acid or base and the initial weight of the compound, the equivalent weight, and thus the number of acidic or basic groups, can be computed. Instead of adding an indicator to observe the equivalence point, one can construct a graph on which the pH (see separate article) ...read more.


to yield H2PO4-, then HPO4-2, and finally PO4-3 , the triply charged orthophosphate ion, usually just called phosphate. An organic example of a triprotic acid is citric acid, which can successively lose three H+ ions to finally form the triply charged citrate ion. Even though the positions of the H atoms on the original molecule may be equivalent, the successive Ka values will differ since it is energetically less favorable to lose a positive H+ if the ion is more negatively charged. Acids are very dangerous. They are extremely reactive with metals and strong acids can give very serious burns just by touching them for an instant. If contact with an acid should occur seek medical attention immediately. Different definitions of acid/base The word acid comes from the Latin acidus meaning sour. In chemistry the term acid has a more specific meaning. The Swedish chemist Svante Arrhenius defined an acid to be a substance that gives up hydrogen ions (H+) when dissolved in water (the product of the solution, H2O + H+, is called a hydronium ion, H3O+), while bases are substances that give up hydroxide ions (OH-). This definition limits acids and bases to substances that can dissolve in water. Later on, Br�nsted and Lowry defined an acid to be a proton donor and a base to be a proton acceptor. In this definition, even substances that are insoluble in water can be acids and bases. The most general definition of acids and bases is the Lewis definition, given by the American chemist Gilbert N. Lewis. Lewis theory defines a "Lewis acid" as an electron-pair acceptor and a "Lewis base" as an electron-pair donor. It can include acids that do not contain any hydrogen atoms, such as iron(III) chloride. Acid/base systems are different from redox reactions in that there is no change in oxidation state. The Lewis definition can also be explained with molecular orbital theory. ...read more.


can combine with one mole of sulfuric acid (H2SO4) to form two moles of water and one mole of sodium sulfate. 2NaOH + H2SO4 � 2H2O + Na2SO4 . Precaution Steps: 1. To fill a buret, close the stopcock at the bottom and use a funnel. You may need to lift up on the funnel slightly, to allow the solution to flow in freely. 2. Before titrating, condition the buret with titrant solution and check that the buret is flowing freely. To condition a piece of glassware, rinse it so that all surfaces are coated with solution, then drain. Conditioning two or three times will insure that the concentration of titrant is not changed by a stray drop of water. 3. Check the tip of the buret for an air bubble. To remove an air bubble, whack the side of the buret tip while solution is flowing. If an air bubble is present during a titration, volume readings may be in error. 4. Place the tip of the pipette in the solution and release your grip on the bulb to pull solution into the pipette. Draw solution in above the mark on the neck of the pipette. If the volume of the pipette is larger than the volume of the pipette bulb, you may need to remove the bulb from the pipette and squeeze it and replace it on the pipette a second time, to fill the pipette volume completely. 5. After the solid is completely dissolved, very carefully fill the flask to the 250 mL mark. Move your eye to the level of the mark on the neck of the flask and line it up so that the circle around the neck looks like a line, not an ellipse. Then add distilled water a drop at a time until the bottom of the meniscus lines up exactly with the mark on the neck of the flask. Take care that no drops of liquid are in the neck of the flask above the mark. Conclusion: After the experiment, we found that the concentration of NaOH is 0. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Aqueous Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Aqueous Chemistry essays

  1. Marked by a teacher

    To determine the amount of ammonia in a sample of household cleaning product, 'cloudy ...

    5 star(s)

    2. An empty beaker was weighed and the mass recorded in Table 1.1. 3. The beaker was kept on the balance and the Na2CO3 added to the beaker until the required amount (as calculated in step 1) was reached. The mass of the beaker and Na2CO3 was recorded in Table 1.1.

  2. Marked by a teacher

    The Effect of pH on the Strength of Keratin (hair protein).

    4 star(s)

    This way hair strength can be calculated. Repeats: The more repeats of each experiment, the clearer the strength of the hairs immersed at different pH, will become. Statistical analysis (standard deviation) is used to eliminate any variance within treatments and calculate a realistic value.

  1. Standardization of NaOH and Analysis of Unknown Acid Sample.

    Begin adding NaOH solution from the buret to the flask, swirling the flask constantly during the addition. It should require at least 20mL of NaOH to properly titrate the solution. The streaks of pink will begin to persist for longer periods of time.

  2. Identification of an unknown organic compound

    Apparatus needed * Water * Phenolphthalein indicator * Water bath * Sodium hydroxide * Unknown organic compound * Test tube Others tests I could have used would be using litmus paper as when litmus is put into an ester substance, it is neutral.

  1. How much Iron (II) in 100 grams of Spinach Oleracea?

    Iron (II) Ammonium Sulphate Mass to be weighed out = Molecular Mass x Moles wanted Molecular Mass = 392.14 Mass to be weighed out = 392.14 x 0.1 Mass = 39.214 g (per 1000 dm-3) 39.214 g 10 = 3.9214 g (per 100 dm-3)

  2. Investigating the effects of varying pH levels on the germination of cress seeds

    Acid rain can significantly affect the growth of plants by damaging root systems, and rendering leaves unable to carry out sufficient photosynthesis (2). * METHOD I began the experiment by labelling the bottles with the concentration of solution that they would hold: 0.1%, 0.3%, 0.5%, 1%, and 10%.

  1. In the first experiment we noticed how Phenolphthalein, thiosulfate and copper (II) sulfate changed ...

    Volume of BaCl Mass of BaSO 5mL 0.17g 10mL 0.41g 15mL 0.54g 20mL 0.76g 25mL 0.85g 30mL 0.93g II. DISCUSSION In this experiment we combined sulfuric acid and aquenous barium chloride to produce a precipitate, barium sulfate, and hydrochloric acid.

  2. Determine the concentration of sulphuric acid by acid-base titration.

    = Mass/Relative Formula Mass 2.65g/106= 0.025 mol dm-3 2) Concentration of NaCO3 = number of moles/volume 250cm� water = 250/100 = 0.25mol dm-� = 0.025/0.25 = 0.1 mol dm-3 (3) calculate the concentration of Sulphuric acid I already know that the ratio is 1:1, as it takes 1 mole of sodium carbonate to react with 1 mole of Sulphuric acid.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work