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To Determine The Concentration Of A Limewater Solution

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To Determine The Concentration Of A Limewater Solution. Aim: To determine the concentration of a limewater solution using hydrochloric acid of a known concentration of 2.00 moldm-3. Ca(OH)2(aq) + 2HCl(aq) --> CaCl2(aq) + 2H2O(l) This shows that the reactants react in a 1:2 ratio. This will be carried out using a titration. However, as the concentration of the calcium hydroxide in the limewater is approximately 1g dm-3 and the concentration of the hydrochloric acid is 2.00moldm-3 the concentration of the hydrochloric acid needs to be reduced. This can be done by a dilution. To make the colour change in the titration distinct and so you know straight away when the solution has been neutralised phenolphthalein indicator will be used, as suggested in Understanding Chemistry. ...read more.


Therefore, it can be diluted by a x100 factor to obtain 0.0200 moldm-3. Method: To dilute the HCl solution. This dilution can be carried out by adding 2.5cm3 of HCl into a 250cm3 volumetric flask and filling to the line with water, i.e. 247.5cm3 of water. The last few drops of water should be added with a pipette. The flask should then be stoppered and shaken to mix the contents. Titration Method: 1. Set up the equipment as shown in the diagram below. 2. Transfer 25cm3 of the lime water to the conical flask using the pipette 3. Add three drops of the indicator into the conical flask. 4. Fill the burette to the max level (0) ...read more.


V represents the average volume of HCl used. As results were calculated in cm3 it must be divided by 1000 to get dm3. Moles can be worked out using the equation 'Concentration = Moles / Volume' i.e. 0.02 x V. The reaction shows that two moles of HCl react with one mole of Ca(OH)2 so in the neutralisation reaction there must have been twice as many moles of HCl than Ca(OH)2 . Therefore moles of Ca(OH)2 must be (0.02 x V) / 2 = 0.01 x V. Using the same equation, Conc. of Ca(OH)2 = (0.01 x V) / 0.025 = 0.4 x V. The mass of the Calcium Hydroxide in the solution can now be worked out using 'n=m/M'. M(Ca(OH)2) = 40 + 2(16 + 1) = 74 Mass of Calcium Hydroxide in dm3 = 0.4 x V x 74 Therefore the concentration of the Limewater in gdm-3 will be: 0. ...read more.

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