To Determine The Concentration Of Limewater Solution

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To Determine  The Concentration Of Limewater        

                                           Solution                                                     

In this experiment I will be determining the concentration of limewater. A titration will be carried out, which will neutralise the limewater, using hydrochloric acid.

The balanced equation for this experiment is:

Ca(OH)2     +       2HCL        -----          CaCl2    +    H2O

Apparatus

                                                                               

  • 250 cm 3 Volumetric Flask                              }
  • Pipette                                                                 }        Used In Dilution Oh Hydrochloric Acid        
  • 25ml 2.00  Hydrochloric Acid                        }

  • Burette
  • Clamp Stand
  •  A Beaker Of 250 cm 3 Limewater With Approximately 1g dm 3 Calcium Hydroxide
  •  A Beaker Of 250 cm 3 Hydrochloric Acid  (diluted x100)  
  • Funnel
  • Pipette
  • Conical Flask
  • Phenolphthalein Indicator         
  • Distilled Water                                                                                                                                                                                  

Hydrochloric Acid

The concentration of hydrochloric acid is too strong,  at 2.00  mol dm3 therefore it needs to be diluted. The reasoning for this is that to be used in its present form for the titration would mean only a very small amount would be needed to neutralise the limewater, which would be very difficult to measure and make the results too inaccurate.         

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To calculate the amount needed to dilute the hydrochloric acid, first I need to find the concentration of Ca(OH)2:

Ca(OH)2    =     1 g dm3

Mr of Ca(OH)2    =   40+ (16 x 2 + 1 x 2)  

                                =  74

1/74                        =  0.0135

                                 = 0.01

In the balanced equation ...

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