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# To determine the relative atomic mass of Lithium

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Introduction

CHEMISTRY ASSESSED PRACITICAL ANALYSIS Aim -: To determine the relative atomic mass of Lithium Lithium is a very reactive metal. In order to determine the relative atomic mass of Lithium, I will be doing it in two ways, namely-: (1) By measuring the volume of hydrogen gas produced (2) By titrating the produced LiOH with HCl To measure the volume of Hydrogen gas produced, I reacted some Lithium metal with distilled water, but firstly I set up the apparatus I'll be using, as illustrated in the diagram below. When measuring the Lithium, safety was an important criterion for me because lithium is a very reactive metal with make cause burns. Firstly I took a clean conical flask of 250cm3, then I took a 100cm3 pipette and rinse it with some distilled water and pipette 100cm3 form the same distilled water into the clean 250cm3 conical flask. I then inserted a stopper that has a delivery tube in it. Later on I took a bowl and fill it up with water but the water was not full in the bowl. I collected 250cm3 of water from the bowl using a measuring cylinder. I then passed on the end of the delivery tube to the mouth of the measuring cylinder, which is filled with water. ...read more.

Middle

LiOH is 1:1, therefore the number of moles of LiOH will be the same as the number moles of HCl in the reaction. That is 3.655 x 10-3 moles of LiOH. Knowing the number of moles of Lithium Hydroxide, I can work out the concentration of the Lithium Hydroxide in the reaction, which will be the same as the concentration when it was produced, by the reaction of water and Lithium metal. That is C = n/v Volume of the Lithium Hydroxide is 25 x 10-3dm3, which is the one I used in the titration C = 3.655 x 10-3 25 x 10-3 = 3.655 = 1.462 x 10-1 moldm3 of LiOH. 25 Going back to the first way the volume of LiOH that was produced was 100cm3 and the concentration will the same as the one during the titration, which is 1.462 x 10-1 moldm3. With this I can work out the number of moles of LiOH in the first reaction I did and then use the stiochiometry ratio of LiOH to Lithium and then use the original mass of Lithium again. The calculation below shows the steps. Concentration of LiOH = 1.462 x 10-1dm3 Volume of LiOH = 100cm3 C = n / v n = C x v = 1.462 x10-1 x 100 x 10-3 = 0.01462 moles of LiOH From the balanced equation in the first reaction. ...read more.

Conclusion

I feel that my results are reliable as they are closer to each other and I have managed to account of the large amount of errors I've made and steps to minimize then in future. THE TRAGEDY OF MACBETH In Act 1, Scene 2 Macbeth is described as 'brave', 'valiant' and 'worthy'. At the end of the play, Malcolm refers to him as a 'butcher'. Write an essay showing how and why Macbeth's character and behaviour change during the play. In the beginning of the play, Macbeth was presented as a hero due to his victory over the Norwegians rebels. Macbeth and his friend Banquo was the King's army. Macbeth fought bravely and the King Duncan rewarded him. On his way home Macbeth encountered some witches, who gave him prophecies that affected him throughout the play. He was told that he was going to be the Thane of cawdor and he was going to be King. Macbeth never took the witches predictions serious since when the Thane of cawdor lives and there is no way he was going to be King since the King Duncan is still alive. Later on, news was brought to Macbeth that makes in more confessed. The news was from the King, telling Macbeth that he is the new Thane of cawdor, immediately when the servants told Macbeth t PATRICK OLANIYI ...read more.

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