Preliminary Calculations
Preliminary Calculations:
Method
Firstly, set up the equipment. In this experiment I am timing to see how long it takes to heat water of given temperatures. I will then fill the kettle up with 500ml of tap water, measuring the water accurately in a measuring cylinder. I will then put the temperature probe in to the kettle at approximately 1cm away from the heating element and ensure that in all my experiments I keep the probe the same distance away from the element because otherwise the temperature of the water will vary throughout the kettle. I will then plug the kettle in and then turn the kettle on and when the temperature reaches 20°C begin the stop clock. Then wait till the water reaches the desired temperature, when it does press the reset button which will give me a lap time, then record the time and again press the rest button which will continue on with the time. When it reaches the next given temperature, press the reset button again and record the lap time and once again press the same button to continue on with timing the heating process, and carrying on repeating this process till I have recorded all the times in my results table.
I will then repeat this experiment 4 more times but to keep the investigation fair, make sure that for every individual experiment………..
- I wash the kettle out thoroughly with cold water to cool the element down, as it will still be warm from the previous experiment.
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I change the water, from hot to cold, so the common starting point remains 20°C for every experiment.
- Use the same common starting point (temperature), because the water’s temperature from the tap can vary slightly.
- I will use the same range of temperatures for each experiment.
In this experiment I am not heating the water to 100°C because it doesn’t always reach this temperature of boiling.
When I have gathered my results, I will need to use some calculations to reach the aim of the experiment, to find out how efficient the kettle actually is.
To work out the efficiency, I can use the simple equation:
Efficiency = Useful energy
Supplied energy - which in my case is:
Efficiency = Heat absorbed by water
Electricity supplied
To calculate the top part of the equation ‘ Heat absorbed by water’, or basically the energy that was successfully used, we use the Specific Heat Capacity of Water, which is 4200J / kg / °C. This means that for every 4200J of energy taken in by every kilogram of mass, by every temperature in crease of one degree.
An example of working out the ‘ Heat absorbed by the water’ for half a litre ( or half a kilogram ), heated up by 30°, I would do
- x 0.5 x 30 = 6300
To calculate the bottom part of the equation, the ‘ Electricity supplied’, I will use the equation E = P x t, I know what the power (P) rating for a kettle is, 2200, and I will have worked out the time in our experiments.
I just have to divide the ‘Heat absorbed by water’ by the
‘ Electricity supplied’ and this will give me the efficiency as a decimal, so just times it by 100 to get the percentage.
Results Tables:
For 500ml (0.5kg) of water.
For 750ml (0.75kg) of water.
For 1 litre (1kg) of water.
For 1.25 litres (1.25kg) of water.
For 1.5 litres (1.5kg) of water.