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To investigate how the concentration of sugar and surface area of cut potato tubes affects potato cells

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Introduction

To investigate how the concentration of sugar and surface area of cut potato tubes affects potato cells - By Mostufa Uddin 10mm Aim The aim of the first investigation is to see if the concentration of sugar affects potato cells. The aim of the second investigation is to see if increasing the surface of a potato tube will affect how fast the process of osmosis takes place for the movement of water in or out of the potato. First investigation - Concentration effects Introduction It is known that liquids move from a low concentrated area to a higher concentration. This is more commonly known as osmosis. The liquids try to balance out the concentration. Osmosis occurs commonly in cells. Substances such as water are diffused into the cell until the concentration from the outside and inside of the cell are equal as possible. Prediction and hypothesis Using the information I have researched, I believe that if the concentration of sugar on the outside of the cell is greater than that of the concentration in the cell, the liquid from the inside of the cell will be drawn out of the cell due to osmosis. This means the cell will decrease in size and therefore weight. If the concentration of the cell is higher then the surrounding liquid, water, will pass through the cell membrane into the cell until the concentration is equal as possible. ...read more.

Middle

The potato tubes in sucrose solution went down in mass while the potato in distilled water went up in mass. These results agree with my hypothesis and predictions. The potato tubes must contain a certain amount of their own sucrose solution in order for water to move through osmosis either way. Conclusion During this investigation I have found out that osmosis does occur in potato cells. When the concentration of the sugar was low, the solution was taken into the potato cell and this is why there is an increase in mass. When the concentration was high in the outside of the solution, solution from the potato cell was released as it tried to balance out the concentration inside and outside the cell. As stated in my introduction, solutions move from a destination of low concentration to an area of high concentration. I know that solution was released or gained because the mass of the potato tube increased or decreased. It was also visible that the potato tube had changed size. The potato that had lost mass had got smaller by 2mm but the potato tube that had gained mass had got bigger by 4mm. I think if I were to do the experiment again I would take more readings and look out for any anomalous results. Evaluation I think the procedure I used was not as accurate as I would have liked because I could not measure exact surface area of the potato tubes. ...read more.

Conclusion

I must stand when doing the experiment and never run for any reason and not cut the potato on my hands. Apparatus Beaker (100cm3) Measuring cylinder 100cm3 Potatoes Cork borer (5mm) Distilled water Electric scales (gram to 2 d.p.) Knife / Tile Diagram Water Water Beaker (100cm3) 2 Potato tubes 1 Potato tube Beaker (100cm3) Water Water Beaker (100cm3) 4 Potato tubes 3 Potato tubes Water Water Beaker (100cm3) 6 Potato tubes 5 Potato tubes Beaker (100cm3) Results table BIBLIOGRAPHY Results table Potato sample (1 or 2) and number of pieces Mass of potato before / g Mass of potato after / g Change in mass / g average change in mass / g Average mass of potato before / g Average mass of potato after / g Percentage increase/ decrease % 1 = 1 piece 1.25 1.324 +0.074 +0.0395 0.9175 0.957 +4.305 2 = 1 piece 0.585 0.590 +0.005 - - - - 1 = 2 pieces 1.39 1.515 +0.125 +0.08 1.0225 1.1025 +7.82 2 = 2 pieces 0.655 0.690 +0.035 - - - - 1 = 3 pieces 1.32 1.435 +0.115 +0.0815 1.001 1.0825 +8.14 2 = 3 pieces 0.682 0.730 +0.048 - - - - 1 = 4 pieces 1.30 1.438 +0.138 +0.1195 0.955 1.074 +12.5 2 = 4 pieces 0.609 0.710 +0.101 - - - - 1 = 5 pieces 1.33 1.468 +0.138 +0.0805 0.9935 1.074 +8.10 2 = 5 pieces 0.657 0.680 +0.023 - - - - 1 = 6 pieces 1.52 1.661 +0.141 +0.0715 1.049 1.1205 +6.82 2 = 6 pieces 0.578 0.580 +0. ...read more.

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