To organise 5 given metals into a reactivity series using 0.2 M Copper (II) Sulphate Solution.

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A SHORT REACTIVITY SERIES

Aim:

To organise 5 given metals into a reactivity series using 0.2 M Copper (II) Sulphate Solution.

Safety:

Before we can even begin, utmost precautions must be taken when it comes to safety. We will ensure that all things that aren’t absolutely necessary are cleared of the bench and placed underneath it, so as to ensure that no one can trip over them. Shirts will be tucked in to prevent any mishaps, and we will be wearing safety goggles, to prevent anything from getting in our eyes. Throughout the entire investigation we will be standing up, to make sure that if there is any major problem on the bench, we will be in a position to do something about it.

We will also have to take precautions when it comes to a metal like calcium. Since it can react with water on skin, we must make sure that it does not come into contact with any part of our body.

Plan:

To be able to produce our reactivity series, we must make use of the fact that a more reactive metal will displace a less reactive metal from its salt solution. When this happens, heat energy is released as the reaction is an exothermic one. The greater the difference in reactivity between the two metals, the more energy released.

This fact allows us to measure the temperature rise and judge from that which metals are the most reactive and which the least.

The reactivity series is a table of metals with the most reactive metals at the top of the table and the least reactive metals at the bottom.

Since I only have 500cm3 of 0.2 molar Copper (II) Sulphate solution and 5 metals, I have decided to test each metals 4 times using 25cm3 of Copper (II) Sulphate solution each time. This maximises the use of the Copper Sulphate Solution.

THE VARIABLES:

The controlled variables:

One of the most important variables that I have to control is how much of each metal I need to use. We must use the same amount of metal each time. However, this does not mean that I must use the same number of grams of each metal, I must use the same number of moles of each metal. We have 0.2 molar Copper Sulphate Solution.

We are lucky that all the metals we have been given to investigate will form 2+ ions in solution. We are also lucky that the SO4 anions have a charge of 2- . This means that when we form equations they will all have molar reacting ratios of 1:1.

X(s)+ Cu2+(aq)SO42-(aq)à X2+(aq)SO42-(aq) + Cu(s)

Where ‘X’ is one of the five metals.

And if X does not react with Copper Sulphate Solution, then we will have:

X(s)+ Cu2+(aq)SO42-(aq) à X(s)+ Cu2+(aq)SO42-(aq)

Either way the reacting ratios will still be 1:1.

So 1 mole of X will react with 1 mole of Copper Sulphate Solution. To make sure the test is fair, we must use the same number of moles of each metal we test.

But, there is a problem we have to deal with first. It will be impossible to put in exactly the right amount of metal to react with the copper sulphate solution. If we add too much metal than some of that metal will not react with the copper (II) sulphate. So we must add copper sulphate solution in excess, so all the metal reacts. To make sure that the copper sulphate is in excess I will work out how much of each metal will react with 20cm3 of Copper Sulphate Solution. This will leave an extra 5cm3 of Copper Sulphate which will ensure that all the metal does indeed react with the Copper (II) Sulphate Solution.

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We can find the number of moles of metal needed to react with 20cm3 of solution by doing the following:

Finding how many moles of Copper Sulphate there are in 20cm3 of 0.2 molar solution.

Moles in solution = molarity x volume of solution

Moles of CuS04=x 20

= 4 x10-3 moles of CuS04 in 20cm3 of 0.2 molar solution.

Since we now know how many moles of Copper Sulphate we have, and since we know the reacting ratios are 1:1, we now know that 4 x10-3 moles of each metal is needed to react with

4 x10-3 moles of copper ...

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