To show the link, if any, between the rate of reaction of hydrogen peroxide and catalase and the surface area of the catalase source (potato).

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 AT1: HYDROGEN PEROXIDE AND CATALASE

Aim

To show the link, if any, between the rate of reaction of hydrogen peroxide and catalase and the surface area of the catalase source (potato).

Prediction

I am going to make 2 predictions on this experiment. The first prediction I am going to make is that the larger the surface area that the particles of hydrogen peroxide have to work on the larger the reaction. The second prediction that I am going to make is that if I double the surface of the catalase source then the reaction will double or if I triple the surface area of the catalase source then the reaction will triple. I have found out that potato is a strong source of catalase and therefore I will use potato as my catalase source in this experiment.

        If you have a 1 cm3 piece of potato then you have 6 cm2 of surface area on which the reactant can react with, but if you cut this into 2 even pieces then you will have an extra 2 cm2 area on which the reactant can react, giving you a total of 8 cm2 surface area. So long as all the surface area is covered with hydrogen peroxide then all the surface area will react, so if you have 6 cm2 and 8 cm2 pieces of potato the                           8 cm2 area will have more reactions causing a higher reaction rate.

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        If you have a piece of potato with a surface area of 6 cm2 and cut it into even parts so as that it has 12 cm2 then you will have twice the reaction, this is because you have twice the surface area for the hydrogen peroxide to work on, and so long as there is enough hydrogen peroxide to completely cover the potato this theory will work. This is called the collision theory. This states that ‘if 1 of the reactants is a solid then breaking it up into smaller pieces will increase its surface area. This means the ...

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