What affect does the concentration of hydrogen peroxide have on the amount of oxygen produced, by the enzyme catalase?

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Anisha Patel

Biology coursework

What affect does the concentration of hydrogen peroxide

have on the amount of oxygen produced, by the enzyme catalase?

Aim ~

My aim is to investigate what concentration of hydrogen peroxide enables the enzyme catalase, found in potatoes to produce the optimum amount of oxygen.

Relevant Background Knowledge

        Enzymes break down big molecules into smaller, more useful ones, for example amylase breaks down starch into sugar. Enzymes are also catalysts, which means they can speed up (or slow down) reactions. They do not get used up or have their shape altered, however they can become denatured after their optimum temperature, usually around 40ºC. The shape of the enzyme changes so it can’t combine with the substance.

        Enzymes are specific. This means that they can only act on one substance. The shape of the enzyme decides what substances it can combine with. The substance molecule fits exactly together with the enzyme, on the active site. This is called the ‘Lock and Key theory.’

For example

Enzyme + Substrate = Enzyme Substrate Complex                 Enzyme + Product

E + S = E S C         E + P

        Catalase is an enzyme found in potato. Factors that affect enzymes are temperature and pH. The concentration of the substrate and surface area of a reactant can also affect an enzyme’s rate of reaction.

        Hydrogen peroxide breaks down into oxygen (O ) and water (H O)

Hydrogen Peroxide                               Water + Oxygen

             2H O                                          2H O  +   O

Variables

        Possible factors to vary are temperature of the hydrogen peroxide, concentration of the hydrogen peroxide and size of the potato chip.

My chosen factor to vary will be concentration of the H O . I can investigate how much oxygen is produced at each concentration by either counting the number of bubbles produced in a fixed rate of time or by measuring the amount of time it takes to produce a fixed volume of oxygen. The second method will be less accurate than the first due to unwanted air bubbles that will always collect in the measuring cylinder used to measure the volume of oxygen produced, preventing the reliability of results. Counting the bubbles produced in a fixed rate of time is an easier experiment to repeat, and therefore averages can be calculated making the data more reliable.

Variables that will remain constant throughout the experiment are ~ the temperature in which the reaction takes place (the water,) the temperature of the hydrogen peroxide, size of the potato chip, amount of H O , length of time used to count bubbles and the apparatus used for the experiment. The temperature in which the reaction takes place, in this case water, and the temperature of the hydrogen peroxide will be controlled by conducting all the tests at room temperature. The size of the potato chip, amount of H O  and the length of time used to count bubbles in will be accurately measured to ensure the experiment is a fair test.

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Prediction and Reasoning

        If testing the H O  in the range 0-20%, I predict that the optimum concentration of the     H O  for catalase will be at 20%. As the concentration of H O  is weakened by half (10% H O ) the amount of oxygen produced in the fixed time will also be halved. This is because the more   H O particles available the more substrate there is for the enzymes to break down, therefore producing a greater amount of oxygen at a quicker rate and visa versa. The less H O particles available the ...

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