Which Equation Is Correct?

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SKILL P: PLANNING        GREIG RAWLINGS        12/02/03

WHICH EQUATION IS CORRECT?

Introduction and Application

  • Copper has two oxides, Cu2O and CuO
  • Copper carbonate, CuCO3 decomposes on heating to form one of the following oxides and an equation can be written for each possible reaction:

Equation 1:        CuCO3(s)                0.5Cu2O(s) + CO2(g) + 0.25O2(g)

Equation 2:        CuCO3(s)                CuO(s) + CO2(g)

  • The task of this experiment is to find out which of the two equations is correct by measuring the amount of gas produced by the reaction.
  • If equation 2 is correct then the following amount of gas should be produced:

Number of grams in 1 mole of copper carbonate (Molecular mass) = 123.5g

Number of grams to use in the experiment = 0.3g

Number of Moles  = Mass / Molecular mass

So therefore:        Number of moles of copper carbonate to use = 0.3g/123.5g

                                        =2.43 x 10-3moles

To work out the volume of carbon dioxide gas produced we use the following equation:                                

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Volume = 24000 x Number of moles

     Therefore:                 Volume = 24000 x (2.43 x 10-3moles)

        Volume = 58.32g or 58.32ml produced from the reaction in Equation 2

  • This gives us the volume for carbon dioxide as the ratio of copper carbonate to carbon dioxide is 1:1
  • For equation 1 however, we must take into account the volume of oxygen. As the equation says 0.25O2 the ratio of copper carbonate to copper oxide is therefore

1: 0.25 -

Volume = (24000 x Number of moles of copper carbonate) / 4

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