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Yeast respiration.

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Introduction

Yeast respiration The possible factors that could affect the reaction are the temperature at which the reaction takes place. The concentration of hydrogen peroxide used, the volume of the hydrogen peroxide used and the area of the catalase that is exposed to the hydrogen peroxide, when the mass of the potato is kept the same. The temperature at which the reaction takes place affects the reaction, as when the temperature is increased the rte of reaction is also increased until the temperature reaches 40 degrees centigrade and he enzymes are denatured. The concentration of H2O2 affects the reaction as when the concentration is increased the reaction is also increased a there is more chance of collision with a higher concentration. The volume of H2O2 used affects the reaction as, when there is more H202 to react with the rate of reaction will take longer because the catalase will have to catylise more H202. When the volume of H202 is increased the rate of reaction decreases. The area of potato that is exposed to the hydrogen peroxide, when increased, increases the rate of reaction also when the mass is kept the same. ...read more.

Middle

The molecules constantly move and bump into each other. When the substrate molecule bumps into a molecule of the right enzyme, it fits into a depression on the surface of the enzyme called the active site. The reaction takes place and the molecules of the product leave the active site freeing it for another substrate to fit into. The active sites are specific shapes so only a certain type of substrate will fit into it. They fit as if they were a lock and key (hence the name). The more molecules there are, the more chance that the enzyme catalase the sub-straight hydrogen peroxide will meet with each other and react, allowing the enzyme to catalyse and increase the rate of reaction. The more the reaction occurs the more oxygen gas and water will be produced. This leads me to a prediction that if the surface area is doubled the chance of collision is also doubled and therefore the rate of reaction and gas produced should also double. This should also be true if you were to triple or quadruple the surface area. Therefore I am going to use the oxygen gas collected to show how the rate of reaction is changed. ...read more.

Conclusion

Therefore my prediction was right. I did the experiment and it worked well so I decided to go ahead and use this experiment and the surface area of the chip as my final factor. When the gas was collected for the smallest area chip it seemed there was not a lot of gas displaced in the measuring cylinder. This was because the cylinder I had used had a very large scale on it. This indicates that I may have to use a smaller measuring cylinder to collect the gas of the chips with a smaller surface area and then change to a larger one for the chips with a larger area. So that the readings can be more accurate. Another samll problem was when I set up my experiment I already had the delivery tube in the water, which meant I got suck back which I notice and decided to set up the experiment and then put the delivery tube in the water so as not to get suck back, which would bring my results down lower, as water would have to be pushed out of the tube. ...read more.

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