Determining the rate of action of an enzyme

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                Mar-10

Determining the rate of action of an enzyme                                                

Skills to be assessed: Design, Data Collection & Processing and Conclusion & Evaluation

Design

Aim:

The purpose of this investigation is to experimentally determine the effect a change in liver surface area will have on the rate of action (measured in oxygen production) of the enzyme (Catalase) on the substrate Hydrogen Peroxide (H2O2).  

Background:

The human body functions due to the action of enzymes which speed up chemical reactions within the body by lowering the activation energy of a reaction.

Hydrogen Peroxide is produced in large amounts within the human body, most notably within the liver.  Hydrogen Peroxide is a by product of various reactions within the body.  It is a toxic chemical and in high concentrations is poisonous to the body systems.  Its prolonged presence would ultimately destroy the body’s cells by inhibiting metabolic reactions.  As a result, the body must find a way of ridding itself of this detrimental Hydrogen Peroxide.  It does this through the implementation of the enzyme Catalase.  

Catalase, like all enzymes adheres to the induced fit relationship between Hydrogen Peroxide and itself.  Accordingly it acts only on H2O2 initiating a reaction, via lowering the activation energy, that results in the breakdown of this harmful substance into harmless substances which can be either used or excreted by the body.   The Hydrogen Peroxide breaks down to form water and oxygen.  This reaction can be seen below:

2H2O2(l)         2H2O(l) +  O2(g)

The Catalase molecules are extremely effective as one molecule of the enzymes can interact with six million molecules of hydrogen peroxide in one minute.

Hypothesis:

It is hypothesised that the rate of action of the Catalase will increase proportionally with the increase of surface area.

This is based on the surface area to volume ratio; by having a higher surface area to volume ratio it will in turn allow more substrate to react with the available enzyme’s active sites until a plateau is reached in the reaction rates where the maximum number of active sites are being bound to by substrates.

The condition of the liver will determine the amount of surface area exposed to the substrate and hence be the definitive factor in this investigation.  Accordingly, the rate of action of the Catalase will be greatest when the liver is ground, it will be followed by the sliced liver and then the whole liver.  This is because the liver with the greatest surface area will have the most hydrogen peroxide molecules converted into oxygen bubbles in the time period.  Reaction rate will then be determined by calculating the number of bubbles produced in the defined time.

Variables

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Materials

Method

  1. Collect materials.
  2. Weigh three (3) approximately cube shaped pieces of fresh liver to be the same weight of 4.00g
  3. Prepare the liver into its three different conditions
  1. Ground- Crush Liver in the mortar and pestle until juice is present.
  2. Sliced- Using a scalpel
  3. Whole
  1. Using the marker, indicate on one (1) test tube the ground liver
  2. Fill the test tube with 20mL of Distilled water.
  3. Add 5mL of 3 % Hydrogen Peroxide to the test tube
  4. Add 10 drops of the dishwashing liquid ...

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