• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Effect of substrate concentration on catalase activity (Biology IA)

Extracts from this document...

Introduction

Title Effect of substrate concentration on catalase activity Aim To prove that at different concentrations of hydrogen peroxide, the rate of catalase activity in chicken liver differs. Hypothesis When chicken liver is exposed to hydrogen peroxide, the higher the concentration of the solution, the faster the activity of catalase because the decomposition rate of hydrogen peroxide increases when its concentration is higher (in the presence of chicken liver). Variables Independent Variables * Concentration of hydrogen peroxide Dependent Variables * Time taken for coloured liquid to rise by 5cm against different concentrations of hydrogen peroxide Controlled Variables * Amount of chicken liver used - cubes cut with a scalpel to approximately 1cm x 1cm x 1cm * Amount of hydrogen peroxide used - 5cm3 measured with a syringe before addition to the chicken liver * Temperature of liver (not controlled) * Age of liver (not controlled) * Source of liver (not controlled) Materials and Apparatus Materials: Apparatus: * 6x Chicken Liver Pieces - 1cm x 1cm x 1cm * 5% Hydrogen Peroxide Solution (5cm3) * 4% Hydrogen Peroxide Solution (5cm3) * 3% Hydrogen Peroxide Solution (5cm3) * 2% Hydrogen Peroxide Solution (5cm3) ...read more.

Middle

Results Pooled data of the time taken for the coloured liquid to rise by 5cm against concentrations of 5%, 4%, 3%, 2%, 1%, and 0.5% hydrogen peroxide: Concentration of Hydrogen Peroxide Solution (%) Time taken for the coloured liquid to rise by 5cm (seconds) ?0.01seconds Reading 1 Reading 2 Reading 3 Reading 4 Reading 5 0.5 29.37 21.10 33.63 30.10 29.81 1.0 12.95 19.02 26.73 25.60 15.31 2.0 9.23 10.34 12.63 10.50 6.12 3.0 5.72 4.81 5.36 4.30 5.24 4.0 2.42 2.34 2.07 3.19 3.84 5.0 0.82 0.92 0.96 1.14 1.53 The average time taken for the coloured liquid to rise by 5cm against concentrations of 5%, 4%, 3%, 2%, 1%, and 0.5% hydrogen peroxide, and the standard deviation: Concentration of Hydrogen Peroxide Solution (%) Average time taken for the coloured liquid to rise by 5cm (seconds) ?0.01seconds Standard Deviation 0.5 28.80 4.63 1.0 19.92 6.11 2.0 9.76 2.38 3.0 5.09 0.55 4.0 2.77 0.73 5.0 1.07 0.28 Calculation's Involved Average time taken for the coloured liquid to rise by 5cm (seconds) ...read more.

Conclusion

higher the concentration of the solution, the faster the activity of catalase because the decomposition rate of hydrogen peroxide increases when its concentration is higher (in the presence of chicken liver). Evaluation The individual chicken liver pieces were not very accurately cut and measured due to their slippery nature. A further way of ensuring equal size of liver pieces could be to weigh them - making sure that the pieces are equal both in size and weight, allowing more accurate reactions and accurate data. When the rubber bung was inserted back into the tube after the hydrogen peroxide had been added, due to the added pressure, the coloured liquid may have been forced up by pressure of insertion, and not just by the reaction between the hydrogen peroxide and chicken liver. In order to avoid severe distortion of results, the rubber bung should be inserted slowly and insertion time should be measured and be equal for each investigation. Also, by collecting data when the coloured liquid had risen to 8cm and 10cm, the results and conclusions would be more extensive and reliable with more data to back them. ?? ?? ?? ?? ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Biology section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Here's what a teacher thought of this essay

3 star(s)

The introduction did not use / introduce any of the scientific theory that is needed to be understood in order to carry out this investigation.
Catalase breaks down hydrogen peroxide in to oxygen and water This was the gas that was being collected (not mentioned). This is found in the liver cells and is useful because hydrogen peroxide is a poisonous substance.
In this investigation choosing hydrogen peroxide as the independent variable was a mistake as all that can be concluded here is that with more substrate there is more product.
However, the data that was collected was good and displayed in a logical and clear table.
A way this investigation could be improved is by making the independent variable the size / mass of chicken liver (as this contains catalase).

Marked by teacher Jon Borrell 22/05/2013

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Biology essays

  1. Marked by a teacher

    IB BIOLOGY INTERNAL POTATO OSMOSIS

    3 star(s)

    4) Repeat the previous process using different concentrations of sugar solutions to replace the water, repeat 4 times using the concentrations 0.1, 0.3, 0.6 and 0.8 mols-1. 5) Write the type of solute each cup contains on the cups with a vivid 6)

  2. Marked by a teacher

    The effect of Pectinase Concentraton on the production of apple juice

    vary and the results may be affected not because of the concentration which will defeat the purpose of this experiment. * Surface Area of Apple - the surface area of apples also affect the outcome of apple juice because if surface area increases, there are more pectin exposed for the Pectinase to react with.

  1. Investigating an enzyme-controlled reaction: catalase and hydrogen peroxide concentration

    The average amount of oxygen produced in 30s (�0.01s)/(�0.25mL) The rate of reaction (mL s-1) Distilled water 0.00 0 5% 1.80 0.06 10% 3.00 0.1 15% 5.00 0.16666 20% 5.60 0.18666 25% 6.20 0.20666 ?Calculations For the average amount of oxygen produced (2% of hydrogen peroxide)

  2. Biology HL IA - Photosynthesis of elodea lab report

    Beaker; 9. Thermometer; 10. Lamp (20W); 11. Stopwatch. Procedure The experiment was done in the dark room. 5g of NaHCO3 was measured using scales and put into 250mL of distilled water. Then, 10 centimeters of Elodea was cut using razor blade and immediately put into the carbonate-filled test tube with the cut end kept up.

  1. To investigate the amount of protein present in different types of milk by measuring ...

    It is because the precipitates are not enough time out of the milk. When adding the solution that contains goat's milk through the cheese cloth. It is filtered very quickly, leading the precipitates did not present in cheese cloth. The soya milk is filtered by filter paper and is left

  2. Effect on temperature on the rate of transpiration of HIbiscus sp

    Record the quantitative and the qualitative raw data in the table shown below. 9. Repeat steps 1 to 8 two times in order to reduce any anomalies.

  1. Osmosis Lab. What is the effect of concentration of blackcurrant squash on osmosis ...

    Concentration of blackcurrant squash solution (%) Volume of blackcurrant squash (cm3) Volume of water (cm3) 0 0.00 30.00 20 6.00 24.00 40 12.00 18.00 60 18.00 12.00 80 24.00 6.00 100 30.00 0.00 3) Collect a potato to cut up and make the chipped potatoes using the borer and cut the chipped potatoes into about 1.00 cm long each.

  2. The Effect of Temperature on the Vitamin C Content of Lemon Juice

    As temperatures effect on vitamin c is permanent this wouldn?t have affected the vitamin c content of the lemon juice but it would have caused the rate of reaction to change as the kinetic energy of the particles would decrease causing them to make fewer collisions therefore reacting slower.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work