• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Examine how the concentration of hydrogen peroxide affects the rate of reaction of the enzyme catalase.

Extracts from this document...


The Effect of Substrate Concentration on the activity of the Enzyme Catalase Aim: Examine how the concentration of hydrogen peroxide affects the rate of reaction of the enzyme catalase. Hypothesis: I believe that as the concentration of the substrate increases, the rate of reaction will also increase. However the reaction will stop when the solution is saturated with the substrate hydrogen peroxide. Background: Enzyme Catalase, are protein molecules found in all living cells. This type of enzyme is found in foods such as potatoe. Enzymes are natural catalyzers, and they are used to speed up reactions and are specific because each one performs one type of reaction. This experiment will show how this enzyme breakdown the hydrogen peroxide molecule by speeding up the decomposition of it into water and oxygen. Equation of this experiment: Catalase Hydrogen Peroxide---------------------->Water + Oxygen Catalase 2H2O2------------------->2H2O+O Variables * Independent variable: Amount of enzymes * Dependant variable: Is the amount of hydrogen peroxide used and the materials such as test tubes and measuring cylinders. ...read more.


Average 18 43 47 60 80% 30 60 90 120 AM 12 55 62 78 JM 12 25 32 39 VC 38 51 71 83 Nico 10 23 30 32 Ch 15 30 52 38 Average 17 37 49 54 60% 30 60 90 120 AM 14 49 60 70 JM 1 12 18 22 VC 9 12 16 20 Nico 15 28 35 40 Ch 5 25 37 42 Average 8.8 25 33 39 40% 30 60 90 120 AM 7 14 40 44 JM 4 10 22 30 VC 11 22 51 60 Nico 22 40 52 57 Ch 22 40 46 50 Average 13 25 42 48 Graph: Conclusion: Our aim was completed, as we could examine how the concentration of hydrogen peroxide affects the rate of reaction of the enzyme catalase. The rate of reaction is increased until the concentration of hydrogen peroxide is saturated at 90s. ...read more.


The reaction is the fastest compared to the other two sections. Section B, there still reaction between them, however it slowed down. Section C, starts at the 90 seconds. I already mentioned that at this period of time the hydrogen peroxide becomes saturated. By watching the graph, we can say that the rate of reaction takes more time to occur. The independent variable, amount of enzymes, was different to the dependant, which was the amount of hydrogen. This was done so, to see the difference between them at the end of the experiment. These differences, has shown us that the more substrate in the reaction, the more product that will be produce. To reduce errors and obtain more accurate results, we maintained the independent variable always constant. Repetition means, reduce of errors. Therefore we should have repeated the experiment three times approximateley. However, there are some errors which, need to take into account. For example, our reaction in order, to start and stop the stopwatch in the correct time. ?? ?? ?? ?? Celina Campo Biology IB ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Biology section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Biology essays

  1. Peer reviewed

    Enzyme Coursework. Investigation to find the effect of substrate concentration on the rate ...

    5 star(s)

    The concentrations used will be: 0.20mol/dm-3 0.40mol/dm-3 0.60mol/dm-3 0.80mol/dm-3 1.00mol/dm-3 Refer to the dilution table (in the method section) for the quantities of hydrogen peroxide and distilled water used to form the solutions. Dependent variable: It will be recorded with a timer (in seconds)

  2. Browning Enzyme

    However, the data that excludes anomalies seems to have a larger spread of data. Conclusion and Evaluation Weakness/ Limitation Evaluation + Significance weakness Possible improvements Design and method of the placing the test -tubes into the water baths: Effectiveness of the use of equipment - a)

  1. Investigating the effect of pH of Hydrogen Peroxide upon the activity of Catalase

    Another uncertainty could be the way I measured the amount of the Catalase enzyme I would use, which came from the chicken liver I used. I cut out pieces of chicken liver and weighed them on an electronic weighing machine so that they were 0.5 kg.

  2. Investigating an enzyme-controlled reaction: catalase and hydrogen peroxide concentration

    I will measure 30 minutes for each concentration of sucrose beaker separately. 5. I could not determine the precise sucrose concentration inside a potato because I could not get the result which there is no change in mass. This problem also can be solved as I use the more small and precise sucrose concentration values.

  1. How pH effects enzyme Catalase in potato cells

    Evaluation The experiment I carried out was suitable as the results and the graph showed no irregular pattern, seeing that my aim and prediction were proved correct, as what I predicted was accurate. I had predicted the 3 main factors that have the potential of influencing the data.

  2. The Effect of Temperature on the Rate of Activity of the Enzyme Catalase in ...

    catalase for the target 40oC catalase temperature data set and the target 60oC enzyme catalase temperature data set. Ho 4: There will be no significant difference between mean relative rate of Enzyme activity of catalase for the target 60oC catalase temperature data set and the target 80oC enzyme catalase temperature data set.

  1. Testing the effect of characteristics of leaves on the transpiration rate of * ...

    = ------------------------ 5 = 0.7 cm -Standard Deviation V ?(x-Mean)2 Standard Deviation = ----------- V n-1 V {(1.6-0.7)2 +(0.6-0.7) 2 + (0.5-0.7) 2 + (0.4-0.7) 2 + (0.4-0.7) 2} = ------------------------------------------------------ V 4 = 0.5 cm Table 3: data required for the calculation of volume of water uptake (cm3)

  2. Determining the rate of action of an enzyme (CONCENTRATION)

    At this point, useful substrate concentration is at its maximum. This is achieved when the amount of useful enzyme present cannot react with any more substrate and hence the graph will cease to increase, but rather stay at the same level if the substrate is continually renewed This is based

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work