• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Investigating Surface Area to Volume Ratio concerning the rate of Diffusion

Extracts from this document...


Investigating Surface Area to Volume Ratio concerning the rate of Diffusion Aim: To determine the relationship between Surface Area and Volume Ratio of a phenolphthalein impregnated agar block, and the rate of diffusion into the block. Description: Diffusion is the passive movement of particles from high concentration to low concentration. It is a very slow process so therefore the smaller the cell it is more efficient and faster. Hypothesis: As the volume of the agar block decreases, the rate of diffusion will increase because the speed of the molecules (movement) is directly associated to the volume. Equipment: - Agar - Sodium hydroxide () solution - Knife - Beaker - Ruler - Stopwatch Variables: Manipulated Variable (MV): volume of the agar cubes. Responding Variable (RV): rate of diffusion and percentage of diffusion. Constant Variable (CV): time, stopwatch, ruler, same bottle of . ...read more.


1 0.70 1.00 0.60 0.76cm 8 0.10 0.20 0.40 0.23cm 18 0.05 0.07 0.08 0.07cm Weighing the amount of present and the amount of agar remaining: Volume of Agar Cube Agar Weight of Cube (g) 1 0.12g 1.59g 1.71g 8 3.45g 4.27g 7.72g 18 6.46g 7.65g 14.11g 32 14.28g 9.27g 23.55g Results: To calculate the percentage of each cube when measuring with a ruler, follow this procedure: 1cm 1cm 1cm Volume of Agar Cube Percentage of present 1 3.8% 8 21.74% 18 71.43% Data Representation: (Graph of above data on sheet attached). Row Mass absorbed (g) Original Volume = Mass % absorbed SA (cm�) Volume (cm�) SA/Vol (cm) 1 1.59 1.71 0.930 6 1 6.0 2 4.27 7.72 0.553 24 8 3.0 3 7.65 14.10 0.542 42 18 2.3 4 9.27 23.60 0.394 64 32 2.0 Conclusion: In conclusion, we tested the Surface Area to Volume ratio in two different ways because we could not decide on which method would be more accurate. ...read more.


We were not able to make all the cubes have the same length, height and depth because the agar was only a certain depth. Although three trials were taken for each agar cube, I still believe that the source of error might have been largely affected by this measurement therefore; we used two methods of finding the percentage of present in the agar cube. We did not make sure that the had a constant temperature so this could have been another factor which affected our experiment. This experiment could be improved by having accurately cut agar cubes as well as another possible way of measuring the absorption of sodium hydroxide. One potential method could be using a jelly mould in order to make sure that all the cubes are the same size and this would make the experiment more accurate. Some of our data was collected during another time and mould started growing on the agar so possibly the experiment was affected by this. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Biology section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Biology essays

  1. Marked by a teacher

    Investigating the relationship between cell size and rate of diffusion

    The surface area of the 3 cm cube was 54 cm, while the volume was 27 cm, giving it a 2:1 ratio. Whilst the surface area of the 2 cm cube was 24 cm, the volume 8 cm, producing a 3:1 ratio.

  2. Biology IA - Investigation of the relationship between surface area and volume using different ...

    After that, cubes are put into NaOH solution and kept there for a period of 10 minutes. When removed from the solution, cubes are dried with blotting paper and cut in half. The distance diffused by a NaOH solution is measured as it is dyed by an indicator in dark pink color.

  1. Surface Area to Volume Ratio Simulation Experiment. The comparison between surface area : volume ...

    10mm � 10mm � 6 = 600mm2 2. (5mm � 10mm � 4) + (10mm � 10mm � 2) = 400mm2 3. (5mm � 10mm � 4) + (5mm � 5mm � 2) = 250mm2 4. 5mm � 5mm � 6 = 150mm2 5. (2.5mm � 5mm � 4)

  2. Modelling Surface Area to Volume Ratio in Cells with Agar Cubes

    As a cell grows its SA/V decreases. At some point in its growth its SA/V becomes so small that its surface area is too small to supply its raw materials to its volume. At this point the cell cannot get larger.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work