Mass of hydrated copper sulfate (g) = (46.08 ± 0.01) – (43.78 ± 0.01) = 2.30 ± 0.02 (g)
Mass of water (g) = ( 46.08 ± 0.01) – (45.22 ± 0.01) = 0.86 ± 0.02 (g)
General reaction: hydrate anhydrous salt + water
CuSO4.xH2O CuSO4 + xH2O
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Mass of hydrated copper sulfate (g) = (46.08 ± 0.01) – (43.78 ± 0.01) = 2.30 ± 0.02 (g)
Mass of water (g) = ( 46.08 ± 0.01) – (45.22 ± 0.01) = 0.86 ± 0.02 (g)
General reaction: hydrate anhydrous salt + water
CuSO4.xH2O CuSO4 + xH2O
m 2.30 ± 0.02 (g) 0.86 ± 0.02 (g)
M 160 +18x (g/mol) 18x (g/mol)
n xH2O (mol) = n CuSO4.xH2O
=
=
(0.86 )(160 + 18x) = )18x
160(0.86 ) + 18x(0.86 ) = )18x
160(0.86 ) = 18x(1.44 0.04)
x = = = 5.3 ± 0.3
Conclusion: The value of x in CuSO4.xH2O is quite similar to the value on the label (literal value) of the hydrated copper sulfate jar (% of difference is 6%)