Wasim Khouri        Chemistry SL

Chemistry Coursework

By Wasim Khouri y12 Sl Chemistry


Contents

Design        

Data Collection and Processing        

Conclusion and Evaluation        


Design

Research Question: How does the dissolved oxygen content vary at different stages of the sewage treatment plant in Istra?

Hypothesis: Dissolved oxygen in water is very important for many plants and animals so that they can undergo aerobic respiration. At a pressure of one atm and a temperature of 20 °C the maximum solubility in water is only about (9 mg l-1) and therefore, I believe that the dissolved oxygen in the water will not exceed 9 mg l-1 at all stages of the water treatment.

 Before I predict what the results will be like, it is vital that you know from what stages of the sewage treatment did I take water samples. The samples are taken from four sections that will be named raw sewage-this is where the water is still very dirty and hasn’t yet been processed at all, air and bacteria tank- here bacteria and air (mainly oxygen) are added to the water, chlorination tank and oxygenation tank.

Oxygen gets into water by diffusion from the surrounding air, by aeration (rapid movement), and as a waste product of photosynthesis. As a result, I believe that raw sewage will have very low dissolved oxygen content due to the fact that it may have a lot of bacteria that will undergo aerobic respiration and that will use oxygen when they decompose. The water taken from the air and bacteria tank is likely to have much higher dissolved oxygen content because air (oxygen) is pumped into the water in order to increase its dissolved oxygen content. However, the bacteria that are added at the same time may be using some of that oxygen and thus will decrease the dissolved oxygen a little. In the chlorination tank, I believe that the dissolved oxygen content will be a little more than the air and bacteria tank because the chlorine will kill any microorganisms that are using the oxygen and hence the dissolved oxygen content will increase as it diffuses from the surrounding air. Finally, I believe that the oxygenation tank will have the highest dissolved oxygen content due to the sheer fact that oxygen is added to the water.     

To carry out this experiment we will be using a modified Winkler method. Manganous ions react with oxygen in the presence of potassium hydroxide to form a manganese oxide precipitate (Step 1). An azide is present to prevent any nitrate ions from interfering with the test. On addition of acid, manganese oxide hydroxide oxidizes the iodide to iodine (Step 2). Since the amount of iodine generate is equivalent to the oxygen in the sample the concentration of iodine is calculated by titration of thiosulfate ions that reduce the iodine back to iodide ions.  

Step 1: 2Mn2+ + O2 + 4OH- →2MnO(OH)2

Step 2: MnO(OH)2 + 2I- + 4H- → Mn2+ + I2 + 3H2O

Step 3: I2 + 2S2O32- → 2I- + S4O62-

Variables:

Join now!

Independent variable: The independent variable in the experiment is the different water samples that we are taking i.e. the raw sewage, water from air and bacteria tank, water from the chlorination tank and water from the oxygenation tank.

Dependant variable: The dependant variable is the dissolved oxygen content because it will vary depending on the place from where we take the water sample.

Controlled Variables: The controlled variables in the experiment would be the dissolved oxygen kit which means that we will be using the same glass bottle, same chemicals and the same syringe in order to keep it ...

This is a preview of the whole essay