• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

IA-Enthalpy Change of Reaction - Zinc and Copper Sulphate.

Extracts from this document...


Chul Ou Lee IB Chemistry 1B ROUGH DRAFT Internal Assessment: Determining An Enthalpy Change of Reaction I. Design Objective: The purpose of this experiment is to determine the enthalpy change for the displacement reaction: Zn(s) + Cu(aq) -> Cu(s) + Zn2+(aq) Introduction By adding an excess of zinc powder to a measured amount of aqueous copper (II) sulfate, and measuring the temperature change over a period of time, you can then calculate the enthalpy change for the reaction by the equation: is the enthalpy change of reaction is the mass of copper (II) sulfate is the specific heat capacity of Copper (II) sulfate solution is the mass of Zn powder is the specific heat capacity of Zn is the temperature change The negative sign is present because the heat gained by the Copper (II) sulfate solution and Zinc is equal to the heat lost by the reaction. The reaction is exothermic and thus the sign would be negative. Materials * Safety glasses and lab coat * Graduated Cylinder * Analytical Balance * Styrofoam cup * Stirring rod * Weighing Boat * Beaker * Spatula * Zinc Powder * 1.00 ...read more.


t1=126 Step 3: Calculate the Final Temperature f(x)=-0.03028x+70.95 Tf=f(126)=67.14 The change in temperature can be found through: Tf-T1 For the example calculation, 67.14-21.8=45.34 Applying the same means of calculation for trials 2,3,4,5, the results can be seen below. Trials Linear Equation T1 Initial Temperature (+/- 0.1) Final Temperature (+/- 0.1) Change in Temperature (+/- 0.1) Average Change in Temperature 1 -0.03028x +70.95 126 21.8 67.14 45.3 44.18 2 -0.03313x+71 129 22.5 66.73 44.2 3 -0.02336x+ 67.47 99 22.4 65.16 42.8 4 -0.02088x +68.39 107 21.9 65.8 43.9 5 -0.03012x+ 69.52 97 21.9 66.6 44.7 *Calculation of Average Change in Temperature Tavg=45.3+44.2+42.8+43.9+44.7=220.9/5=44.18oC Calculating the Enthalpy Change of Reaction To calculate the enthalpy of reaction, the following equation will be used: =44.18oC =25g =6.08g =4.181 Jg-1oC-1 =0.39 Jg-1oC-1 Hence, -(44.18)((25)(4.181)+(6.08)(0.39)) =-4722.67J Now, we must change the value to he correct form because the value (-4722.67J) is the enthalpy change of the reaction when 25mL of 1M CuSO4 reacts, but we want to find the enthalpy change of the reaction per mole of CuSO4 in kJ/mol. ...read more.


When the temperature probe is located closer to the bottom of the Styrofoam cup, the probe would naturally pick up higher temperature, while when it is closer to the top of the solution, the temperature would be lower. Improvements * Two or more Styrofoam cups, or other cups with better heat retention ability can be used. * A hexagonal stirring rod can be used to minimize the clash between the temperature probe and the stirring rod. * The graph can be stopped for the split second while the lid is open to minimize the impact of the opening of the lid on the graph. Also, a better lid with airtight and temperature retention ability can be used. * Acetone cleaner may be used to clean the equipment due to its high volatility and a dryer could be used to make sure that all equipment are well dried and isolated. * More solution can be used for the experiment, allowing more distance between the bottom of the solution and the top. This way, the temperature probe can have a larger leeway and be placed in the center. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Chemistry essays

  1. Determining an enthalpy change of reaction

    The enthalpy change for the quantities used: Sample calculations: M = 25*1.64 = 26.64 C = specific heat capacity of water = 4.18 ?T = (Tf - Ti) = (21.6 - 22.5) = -0.9 ?H = MC?T = 26.64(4.18)(21.6 - 22.5)

  2. Hesss Law Lab, use Hesss law to find the enthalpy change of combustion of ...

    RU ( c) = 0 ( table value ) So percentage uncertainty for RU(Q)=RU(m)+ RU(?T) RU(Q) = 2+ 12.5 = +/- 14.5 % Now, the absolute uncertainty for MgO's mass is, AU(m(MgO))=+/-0.01 g Then RU(m(MgO))= (AU(m(Mg))/ m(Mg))*100% RU(m(MgO)) = (0.01/0.40)*100 = 1/0.40 = � 2.5 % As AU(M(Mg))=0 because this value is given and not calculated by us so, RU(n)

  1. IB IA: Determination of Heat of Neutralization

    Sulphuric acid is a dibasic acid that produces 2 moles of hydrogen ions upon dissociation in water. Thus, when the ions are reacted with sodium hydroxide or potassium hydroxide, 2 moles of water molecules are formed. Thus, heat released in such neutralization reactions is twice as much as the

  2. Thermodynamics: Enthalpy of Neutralization and Calorimetry

    g 76.028 g Mass of Metal Cylinder 17.715 g 17.771 g 17.751 g Mass of Cold Water 69.133 �.001 g 67.634 �.001 g 68.240 �.001 g 68.336 �.001 g Temperature of Cold Water 21.7 �.5 C� 21.3 �.5 C� 22.0 �.5 C� Temperate of Cylinder 97.1 �.5 C� 95.3 �.5

  1. Effect of Current on The Quantity of Products in Copper Purification Through Electrolysis

    2,50 1,5100 1,5650 0,055 13 2,50 1,5500 1,6250 0,075 14 2,50 1,5650 1,6500 0,085 15 2,50 1,5050 1,5550 0,050 16 3,50 1,5950 1,6600 0,065 0,064 17 3,50 1,5500 1,6200 0,070 18 3,50 1,4950 1,5600 0,065 19 3,50 1,5500 1,6200 0,070 20 3,50 1,6300 1,6800 0,050 21 4,50 1,6050 1,6780 0,073

  2. Experiment Plan. Chemistry IA: Electrolysis of Metal Sulphate solutions (NiSO4)

    The nickel sheet electrodes will be 10mm by 50mm long. This is measured using a ruler. Equipment Equipment such as measuring cylinders, power packs, wires will need to be the same. This is because different equipment would have different uncertainties, which may affect the final readings of the experiment.

  1. The aim of this experiment is to examine the enthalpy of combustion of the ...

    = 1.59 g ( as decided ) Molar mass of methanol is needed for further calculations and it can be calculated in a following way : M (CH3OH) = Ar (C) + Ar (O) + 4*Ar (H) = 12.01 + 16.00 + 4*1.01 = = 32.05 g mol-1 From here

  2. Electrolysis of copper sulphate

    1 x tile or matt 1. 5x 100mL beaker 1. 10 x red wires 1. About 500 mL of 1 mol/L Copper (II) sulphate solution 1. 12 x black wires Safety This experiment is relatively safe to perform if the necessary precautions are met, the following safety measures are necessary for your protection.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work