im To determine the relative molecular mass of chloroacetic acid ClCH2COOH

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Aim

To determine the relative molecular mass of chloroacetic acid (ClCH2COOH).

Data Collection

Table (1): masses of items used in the experiment.

Table (2): volume of solutions used in the experiment.

  • Two drops of phenolphthalein indicator were added to the chloroacetic acid solution to enable us to determine when the solution is neutralized. Phenolphthalein is pink in basic and neutral solutions and colorless in acidic solutions.

  • When 20.8 cm3 ± 0.1cm3 of sodium hydroxide were titrated into the flask containing 10.00cm3 ± 0.06 cm3 chloracetic acid and two drops of phenolphthalein indicator, the color of the solution changed from colorless to pink, which indicates that the solution has been neutralized.

Data Processing and Presentation

1.        Number of moles of sodium hydroxide reacted

Conversion factor

1 cm3 = 10-3 dm3 

20.8 cm3 = 20.8 * 10-3 dm3 = 2.08 * 10-2 dm3

Number of moles (n) = concentration (c) * volume (v)  

                       =   (2.08 * 10-2) (0.10)

                                    =    2.1 * 10-3 moles of sodium hydroxide reacted

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2.        Number of moles of chloroacetic acid reacted

Chloroacetic acid (ClCH2COOH) reacts with sodium hydroxide (NaOH) to produce sodium chloroacetate (CClH2COONa) and water (H2O) according to the following equation:

ClCH2COOH (aq) + NaOH (aq) →CClH2COONa (aq)  + H2O (l) 

From the equation we see that:

1 mole of ClCH2COOH → 1 mole of NaOH

x                            → 2.1 * 10-3 mole NaOH

Number of moles of ClCH2COOH reacted  = x =  1 * 2.1 * 10-3 =  2.1 * 10-3 mol

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