• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3

# Investigation 1 ANALYSIS OF BAKING SODA

Extracts from this document...

Introduction

Investigation 1 ANALYSIS OF BAKING SODA ?Aim? Determine the mass percentage of NaHCO3 in the sample. ?SAFETY? a. Wear safety goggles and a laboratory apron in the laboratory at all time. b. Notify your teacher immediately if any chemicals, especially concentrated acid or base, are spilled. ?BACKGROUND? Titration is usually the case when insoluble solid reagents are used. Back titration is usually employed for quantitative work with substances of this kind. In this investigation we use back titration to determine the mass of baking soda. Then we can calculate the percent error of the experimer. The amount of solute can be calculated from the volume of the solution of known concentration. The amount of the unknown may then be found using the balanced equation. Finally the concentration of the second solution used. ...read more.

Middle

Conclusion

NaHCO3 � NaCL + H2O + CO2 HCL: NaHCO3 = 1:1 nNaHCO3 =0.0133 mol m = n � M =0.0133�84.01 =1.117333 g The percentage error: (2.021-1.117333) � 1.117333=80.88% 3. HCL + NaOH � NaCL + H2O NaOH: HCL = 1: 1 nNaOH=C�V=1.00�6.2/1000 = 0.0062 mol nHCL = 0.0062 mol nHCL = C�V =1.00�19.6/1000 = 0.0196 mol nHCL = 0.0196 - 0.0062 = 0.0134 mol nHCL + NaHCO3 � NaCL + H2O + CO2 HCL: NaHCO3 = 1:1 nNaHCO3 =0.0134 mol m = n � M = 0.0134�84.01=1.125734 g The percentage error: (2.025-1.125734) � 1.125734=79.88% ?DISCUSSION &CONCLUSIONS? In investigation one, we could not use the equipment very well. When we added the NaOH, the solutions have been red but we did not stop it. At next investigation we need to more carefulness. ?Reference? John Green & Sadru Damji �Chemistry� For use with the International Baccalaureate Diploma Programme 3rd Edition ?? ?? ?? ?? 1 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Chemistry section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related International Baccalaureate Chemistry essays

1. ## Preparation of ear drops practical. Titration of NaHCO3

Molar of mass of NaHCO3 = 84 grams moles x molar mass- 0.61 x 84 = 51.24 grams per litre. To calculate the amount per 100ml divide it by 10 51.24/10= 5.124 grams per 100 ml The calculated amount

2. ## Airbag design lab. Is it possible to use baking soda, NaHCO3(s), and 2.00 ...

measured in the beginning (this is because the HCl will occupy the space of the bag once it is added) 8. Using the ideal gas law again, plug in the new subtracted volume into the formula to figure out the moles of NaHCO3.

1. ## Effect of concentration on Nacl solution

This giving us an idea of how the electric conductance of the solution would change when the concentration of the solution is increased or decreased. So then from the experiment we can draw a conclusion on how the concentration of a solution affects the conductivity of an ionic solution.

2. ## Espuma a base de cscara de pia

y Hexa (HDI). A continuaci�n les voy a mostrar las f�rmulas estructurales y los nombres de cada uno6: Tolueno-2,4-diisocianato (TDI) Naftalina-1,5-diisocianato (NDI) O=C=N--- (CH2)6---N=C=O Difenilmetano-4,4-diisocianatos (MDI) Hexa-1,6-diisocianato (HDI) La forma hexagonal que se presenta en el TDI, NDI y

1. ## Enthalpy of Neutralisation Between HCl and NaOH

While it is unsure how large the experimental error was in comparison to random error, there are several possible factors for the large experimental error. The first and most prominent of these reasons is the likelihood of energy being lost from the system to the surroundings.

2. ## Research question: how to convert NaOH to NaCl by two different routes , and ...

1.00 g/cm3= which implies that mass of water = 1.00 x 50.0 = 50.0 g ___________________________________-- Table 1 : the table below shows the raw data collected when adding 4.0 g of sodium hydroxide NaOH to 50.0 cm3 of water H2O in the thermos and measuring the temperature change for 450 seconds using labQuest when applying route (A), : 1.

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to