Lead Iodide Precipitate Lab Report

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Chad Brelsford

Lead Iodide Precipitate Lab Report

Introduction

Problem: What mole ratio of lead chloride and sodium iodide results in then greatest amount of lead iodide as a precipitate?

Hypothesis: If I mix 2 ml of lead chloride and 3 ml of sodium iodide, then I will get the greatest amount of precipitate.

Variables:

  • Independent: amount of PbCl2, amount of NaI
  • Dependent: amount of Lead Iodide formed
  • Constants: amount of water, resting position of the cuvettes, Temperature, concentration of the PbCl2 solution, concentration of the NaI solution
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Procedures

Materials:

12 empty cuvettes, a cuvette holder, a ruler with mm measurements,

2-10ml graduated cylinders, 0.35 solution PbCl2, 0.35 solution NaI

Procedures:

1. Pour 4 ml PbCl2, and 1 ml NaI into three cuvettes and label as group A.

2. Pour 3 ml PbCl2, and 2 ml NaI into three cuvettes and label as group B.

3. Pour 2ml PbCl2, and 3 ml NaI into three cuvettes and label as group C.

4. Pour 1ml PbCl2, and 4 ml NaI into three cuvettes and label as group D.

5. Place all 12 cuvettes in a cuvette holder, ...

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