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Tetraamminecopper(II) sulphate hydrate

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Tetraamminecopper(II) sulphate hydrate Write-up Purpose The purpose of this experiment is to form tetraamminecopper(II) sulphate hydrate and determine the yield. Materials CuSo4�5H2O NH3 (concentrated) Ethanol 50 cm3 measuring cylinder 250 cm3 beaker Spatula Equipment for vacuum filtration Procedure Weigh out approximately 5.0g of CuSo4�5H2O Dissolve it in 30 cm3 water in the beaker Add 10 cm3 concentrated ammonia (NH3) and stir the solution Add 40 cm3 ethanol and stir carefully for a couple of minutes. Filter the solution through equipment for vacuum filtration. Transfer the product to a clean weighing boat and leave to dry. Procedure and observations in class First 5.01g of CuSo4�5H2O was weighed out. ...read more.


Mr = 64 + 32 + (16 x 4) + (5 x 16) = 250 m = 5.01 n = 5.01 / 250 = 0.02004 � 0.0200 moles (3 s.f.) 2. "Concentrated ammonia contains 25% NH3 by mass. The density of concentrated ammonia is 0.91g/cm3 . Calculate the number of moles of NH3 ." Density of con. ammonia = 0.91g/cm3 and in the procedure there was used 10 cm3, so therefore mass of ammonia used: 0.91 x 10 = 9.1g Since only 25% of ammonia is NH3 , mass of NH3 : 9.1 x 0.25 = 2.275g From here the amount of moles can be calculated by the formula n = m / Mr. Mr = 14 + (1 x 3) ...read more.


5H2O and Cu(NH3)4SO4 . H2O is 1 : 1. Therefore 0.02 moles of CuSO4 . 5H2O will give 0.02 moles of Cu(NH3)4SO4 . H2O. By using the formula m = Mr x n the theoretical yield can be calculated: n = 0.02 Mr = 246 m = 0.02 x 246 = 4.92 g "Calculate the yield in percentage of the theoretical and comment on any difference." The yield in percentage can be calculated by the "formula": actual mass / expected mass. 4.82 / 4.92 � 97.9% (3 s.f) Because the difference is so small (2.1%) the experiment can be considered successful. The difference could have been caused by different things like: a small measurement mistake, a little bit was spilt or not transferred when the solution was held in the Buchner flask. ...read more.

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