• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

The Relative Formula Mass of a gas by Effusion

Extracts from this document...


The Relative Formula Mass of a gas by Effusion. Name: Suleman Esam Date: 25/10-07 Purpose The purpose of this experiment is to determine the unknown in the following acid base reaction: H X(g) + NH3(g) ? NH4Cl(s) Background Effusion is escape of molecules through a small hole. Some gases effuse faster then others. According to the Graham's law, the rate at which a gases effuse depend on their mass. Graham's law tells us that the rate of effusion of a gas is inversely proportional to the square root of its relative formula mass. Equipments - Glass tube - Cotton swabs - NH3 - Acid - Goggles - Gloves - Crucible tongs - Ruler Procedure 1. ...read more.


4. As a final point, we recorded the distance between the reaction point and the two ends. Result The compound of base and acid were: 19.6 cm = 20 cm �1 cm (4.76%), away for the acid 31.4 cm = 30 cm �1 cm (3.23%), away from the base The distance that the molecules travel is proportional to the kinetic energy. The kinetic energy is given by: KE= 1/2mv2 In this case, since they both had the same temperature, the will look like this: KEA=KEB 1/2mvA2= 1/2mvB2 mAvA2= mBvB2 vA2/vB2= mB/mA vA/vB= V(mB/mA) "v" (velocity) stands for rate of effusion. ...read more.


Y= 38 �7.99% Conclusion The molar mass of the acid is 38. The acid contains one hydrogen atom, so the molar mass of the X is 37. Now there is no atom with molar mass of 37, so the two closest atoms to this molar mass are Cl and AR. When Cl binds with hydrogen, they form an acid, so X is Cl. With that known, we can complete the formula for the reaction. HCL(g) + NH??g??? NH4Cl(s) Errors - The two cotton swabs might not have been plugged inn simultaneously into the tube. - The solid that was made between the base and acid, had an area of approximately 2 cm and that increased the uncertainty. Improvements The experiment could have been more effective, if we had repeated the experiment several times to get a more precise result. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Chemistry essays

  1. im To determine the relative molecular mass of chloroacetic acid ClCH2COOH

    Human parallax error in taking mass measurements: the scales of the triple beam balance might not have been viewed at right angles. 3. The end point might not have been reached. This means that a greater volume and therefore a greater number of moles of sodium hydroxide were needed to completely neutralize the 2.00g of chloroacetic acid.

  2. Can one determine the coefficients of a balanced chemical equation by having the mass ...

    This would form copper(ii) oxide which is not a desirable product and would add to the mass of copper at the end since it is not soluble in water. Even though the aluminum was shined quite a lot to get rid of the oxide, it is inevitable that there is some aluminum oxide left since aluminum oxidizes very quickly in the presence of air.

  1. Espuma a base de cscara de pia

    Poliol: es un compuesto qu�mico que contiene m�s de un grupo hidroxilo a�adido a una mol�cula5, y por esto son considerados alcoholes. El glicol es un poliol ya que este es una mol�cula que contiene dos grupos hidroxilos en carbonos vecinos.

  2. Determining the relative atomic mass of Lithium

    The Li was taken out of the container at the beginning of the experiment so it could be used by other students thus leaving time for the oxide to form. This would have increased the mass of lithium as LiO has a greater Mr than Li, thus would have increased our value for the relative atomic mass of lithium.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work