• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

TITRATION OF A WEAK ACID WITH A STRONG BASE - From the experiment I have calculated that the molar enthalpy of neutralization for sodium hydroxide wiht sulphuric acid is -(54 3.2 kJ/mol).

Extracts from this document...


LAB #7:TITRATION OF A WEAK ACID WITH A STRONG BASE Submitted by Tim Kwok Chemistry 20 IB Presented to Ms. Gierach December 11, 2009 Design Problem: Refer to teacher sheet. Prediction: Materials: * 10mL pipette * a burette * 150mL beakers * pH meter * a retort stand * sodium hydroxide acid solution * weak acid solution Procedure: Refer to teacher sheet. Variables: Data Collection and Processing Quantitative Data: Pipette (mL) ?0.04mL : TITRATION OF WEAK ACID WITH STRONG BASE POTENTIOMETIRC TRIAL Burette Reading (mL) ?0.05mL pH ?0.01 Burette Reading (mL) ?0.05mL pH ?0.01 12.50 2.95 18.55 10.88 16.80 5.18 18.60 11.09 17.00 5.30 18.65 11.20 17.20 5.37 18.70 11.30 17.25 5.40 18.75 11.36 17.50 5.48 18.85 11.45 17.60 5.54 18.90 11.50 17.70 5.64 18.95 11.52 17.80 5.67 19.00 11.56 17.90 5.74 19.05 11.59 18.00 5.84 19.10 11.61 18.05 5.88 19.15 11.63 18.10 5.97 19.30 11.68 18.20 6.11 19.55 11.74 18.25 6.20 19.95 11.77 ...read more.


= 8.00?0.4�C (0.050L ? 0.0002L NaOH(aq)) * 1mol NaOH(aq) * ?rHm, NaOH = (0.080 ? 0.0004kg H2O(l)) * 4.19 kJ * (8.00? 0.4�C) 1L NaOH(aq) kg * �C (0.050L ? 0.4% NaOH(aq)) * 1mol NaOH(aq) * ?rHm, NaOH = (0.080 ? 0.50% kg H2O(l)) * 4.19 kJ * (8.00? 5.0%�C) 1L NaOH(aq) kg * �C (0.050 ? 0.4% mol NaOH(aq)) * ?rHm, NaOH = (2.6816... ?5.5% kJ) ?rHm, NH4Cl = (2.6816... ?5.5% kJ) (0.050 ? 0.4% mol NaOH(aq)) ?SolHm, NaOH = 53.632... ?5.9% kJ/mol ?SolHm, NaOH = 53.632... ?3.164288... kJ/mol ?SolHm, NaOH = 54 ?3.2 kJ/mol Temperature increases = exothermic reaction = -(KJ/mol) so: ?SolHm, NaOH = -(54 ?3.2 kJ/mol) Percent Error: ?(?57 kJ/mol -54 kJ/mol?) / 57 kJ/mol?*100% = 5.236...% ?(?57 kJ/mol -54 kJ/mol?) / 57 kJ/mol?*100% = 5.3% Conclusion and Evaluation Conclusion: From the experiment I have calculated that the molar enthalpy of neutralization for sodium hydroxide wiht sulphuric acid is -(54 ?3.2 kJ/mol). ...read more.


In actuality the product of the neutralization has it's own specific heat capacity, this means that the calculations are off by a bit since the actual specific heat capacity was not used. Improvements: In order to close the system off even more, you can tape all the cracks that are visible on the calorimeter so that less energy is lost between the system and the environment. To fix the problem of thermal energy being lost by calorimeter material, just calculate the quantity of thermal energy each material loses and subtract it from you final temperature to compensate for the specific heat capacity of the other materials. This gives you the actual Q of the product, and since Q = mc?t and n?rHm = mc?t, n?rHm = Q. The last improvement that can be made to the experiment would be to use the actual specific heat capacity of the product rather than just 4.19 J/g * �C. All these improvements will help bring the calculated value closer to the theoretical value minimizing the percent error. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Chemistry essays

  1. Free essay

    pH titration curves Lab Report. How does the use of a strong acid with ...

    Phenolphthalein will be used throughout the experiment. - volume of the unknown concentration of acidic solution The volume of the unknown concentrations of acidic solutions will be the same (30 mL) throughout the experiment. This could give accurate readings for the pH titrations and help plot more accurate pH curves.

  2. Free essay

    Titration of a weak acid with a strong base

    pH and volume readings were noted down, as shown in the table below. A titration curve was then plotted. pH (weak acid) Volume in ml (NaOH) �1 pH (weak acid) Volume in ml (NaOH) �1 1.98 0 11.12 18.8 2.45 2 11.35 19 2.63 3 11.51 19.2 2.78 4

  1. IB IA: Determination of Heat of Neutralization

    � K2SO4(aq) + H2O(l) Heat evolved = mc? = 0.1 x 4.18 x 12.50 = 5.225 kJ Number of moles of acids used = 1 x 0.05 = 0.05 moles From the equation, 1 mole of H2SO4 reacts with 2 moles of KOH and gives 2 moles of water.

  2. The Enthalpy of Neutralization

    Data Processing Experiment 1 - Enthalpy of neutralization for hydrochloric acid and sodium hydroxide NaOH(aq) + HCl(aq)-->NaCl(aq) + H2O(l) Finding the Moles of Water Moles of hydrochloric acid: [Volume x Concentration] 0.025dm3 x 2.00mol�dm-3 = 0.050mol HCl Moles of sodium hydroxide: [Volume x Concentration] 0.025dm3 x 2.00mol�dm-3 = 0.050mol NaOH

  1. Hesss Law Lab, use Hesss law to find the enthalpy change of combustion of ...

    heat loss means that the values obtained for heat loss are slightly lower than those of Table values. Finally, due to the time restrictions and chemical limitations implemented during this lab, further trials were unable to be completed to ensure the accuracy of this lab.

  2. Experimental Molar Enthalpy of Neutralization for Sodium Hydroxide Solution

    This as a result produced a 12% difference. The various errors will be analyzed in the evaluation. Evaluation As discussed earlier in the conclusion, the experimental change in enthalpy is greater than the theoretical (actual) change in enthalpy. This result is quite rare. In general, a typical result for the experimental enthalpy change should yield an outcome lower than the theoretical (actual)

  1. The aim of this experiment is to examine the enthalpy of combustion of the ...

    energy will be needed to break those bonds.Once they are broken more energy will be released during the combustion , because more carbon- oxygen bonds ( within carbon- oxides ) are being formed at that time. Therefore ,the larger the alcohol molecule, the more bonds will be broken and formed, and therefore the more heat will be produced.

  2. Chemistry Titration Acid Base Lab

    However, when the base is added and the endpoint has been reached, the color changes to a dark blue shade. If over titration occurs, the solution will remain blue. 21.20 21.60 0.4 21.60 22.00 0.4 Data Processing Table B: A Representation of the Volume of Sodium Hydroxide that was Required

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work