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# To calculate the percentage composition of the mixture of Na2CO3 + NaHCO3

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Introduction

Chemistry lab report 4 Aim - To calculate the percentage composition of the mixture of Na2CO3 + NaHCO3 Procedure 1) Weigh a perfectly dry crucible with properly fitted lid. 2) Weigh the crucible with 1 gram of the mixture. 3) Heat the crucible with a partially open lid for 10 minutes with low flame and gradually increase the flame. 4) Keep heating for 30 minutes. 5) Place the crucible to a dessicator. 6) Weigh the cooled crucible and note it down. Equipment used - 1) Crucible 2) Weighing machine 3) Dessicator 4) Bunsen burner 5) Tripod stand 6) Lighter 7) The mixture Qualitative analysis - 1) The cooling process was time consuming. 2) When the heating started, there were some fumes evolved. 3) ...read more.

Middle

After Heating, Mass of the crucible + 0.001g Mass lost after heating + 0.002g 1 27.385 28.222 0.837 28.000 0.222 2 30.238 31.188 0.950 30.951 0.237 DATA PROCESSING 2NaHCO3 ---- Na2CO3 + CO2 + H2O Molar mass of 2NaHCO3 = 168 Molar mass of CO2 + H2O = 44 + 18 = 62 As we know the mass of - CO2 + H2O = 0.222 + 0.002g in the first attempt. This was calculated by Mass lost after heating = (Mass of crucible + mixture) - (After heating mass) This mass loss is the mass of H2O + CO2 which evaporates during the heating process. ...read more.

Conclusion

Therefore, the uncertainty for the final value of NaHCO3 71.9 + 0.4% And Na2CO3 = 28.1 + 0.4% Because the percentage uncertainties are added. The final answer for the second attempt was = NaHCO3 = 67.6 + 0.3 % Na2CO3 = 32.4 + 0.3% Conclusion - My final result would be 30.25 + 0.6 % as it is the average of both the attempts made. The real value of the composition is 30 % It is quite close and can be concluded that the answer is not exact due to some human errors or impure mixtures. Evaluation - 1) The answer could have been more accurate and precise if I would have repeated the experiment once more. 2) Could have used better equipment with more precise readings 3) Made sure that the mixture used was pure. ?? ?? ?? ?? ...read more.

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