We measured the change of temperature of two reactions to determine the enthalpy change of the third. We first theoretically calculated the enthalpy and then performed experiments.

Authors Avatar

Shazde Mehkri

11/12/08

Enthalpy change of a chemical reaction

Data:

Final temp. is calculated by  Y = mx + b

For reaction1: 0.00648(11)+36.2 = 36.27

        

(See attached graphs)        

(Values of m,x & b are  taken from graph)

                        

Sample calculations:

Run 1: Change in Temp. = Final Temp. – Initial Temp.

13.53° C = 36.27° C – 22.74° C

(Similar calculation done for Run 2 and Run 3)

Data processing:

Reaction 1:NaOH + HCL  NaCl + H2O

Net ionic equation:

 H+ + OH-  H2O

Theoretical   H for reaction 1: -(H Products – H reactants)

Join now!

(-286 – (-230) = 56

Reaction 2:NaOH + NH4OH  NH3 + H2O

Net ionic equation:

NH4+ + OH-  NH3 + H2O

Theoretical   H for reaction 2: -366 – (-362) = -4

Reaction 3:HCL + NH3  NH4Cl

Net ionic equation:

NH3  + H+ + Cl-  NH4+ + Cl-

Theoretical   H for reaction 3: -247-(-299)=52

 

Therefore according to Hess’s law 2 reactions are added to get the  H of third

R3= R1 + R2

52= 56 + -4

        

Further calculations:

 

Experimental Q = mc  t

For run 1:reaction between NaOH and HCL

NaOH + HCL ...

This is a preview of the whole essay