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A logistic model

Extracts from this document...

Introduction

IB Mathematics HL Type II Portfolio: Creating a logistic model        International School of Helsingborg – Christian Jorgensen

Creating a logistic  model

Christian Jorgensen

IB Diploma  Programme

IB Mathematics HL Portfolio type  2

Candidate number

International School  of Helsingborg, Sweden

1


IB Mathematics HL Type II Portfolio: Creating a logistic model        International School of Helsingborg – Christian Jorgensen

Theory

A logistic model is expressed as:


un+1  =run


{1}

The growth factor r varies according to un. If r=1 then the population is stable.

Solution

1.   A hydroelectric project is expected to create a large lake into which some fish are to be placed. A biologistestimates that if 1x104 fish were introduced into the lake, the population of fish would increase by 50% inthe first year, but the long-term sustainability limit would be about 6 x104. From the information above, write two ordered pairs in the form (u0, r0), (u0, r0) where Un=6x104. Hence, determine the slope and equation of the linear growth in terms of Un

As Un =6 ×104 , the population in the lake is stable. Thus from the definition of a logistic model, r must equal to 1 as un approaches the limit. If the growth in population of fish (initially 1 ×104 ) is 50% during

the first year, r must be equal to 1.5. Hence the ordered pairs are:

(1×104 , 1.5) ,  (6 × 104 ,  1)

One can graph the two ordered pairs. It has been requested to find the growth factor in terms of Un, and thus one should graph the population (x-axis) versus the growth factor (y-axis):

2,5

2,4

2,3

2,2

2,1

2

image00.png1,9

1,8

1,7

1,6

1,5

1,4

1,3

1,2

1,1

1


Plot of population U n versus the growth factor r

Trendline

y = -1E-05x + 1,6

0        10000        20000        30000        40000        50000        60000        70000

image01.pngFish population Un

Figure 1.1. Graphical plot of the fish population Un versus the growth factor r of the logistic model un+1  =run

2


IB Mathematics HL Type II Portfolio: Creating a logistic model        International School of Helsingborg – Christian Jorgensen

The slope of the trend line in figure 1 is determined graphically.

...read more.

Middle

105 )(1×104 ) +c

c = 2.9  (3.8 × 105 )(1× 104 ) = 3.28

Hence the equation of the linear growth factor is:

r  =3.8 ×105 u


+ 3.28


{10}

n        n

Using equations {1} and {2}, one can find the equation for un+1:

11


IB Mathematics HL Type II Portfolio: Creating a logistic model        International School of Helsingborg – Christian Jorgensen

un+1  =run

r  =3.8 ×105 u


+ 3.28

n        n

un+1


= (3.8 × 105 u


n  + 3.28)un

= (3.8 ×105 )(u


)(u


) + 3.28u

The logistic function model for un+1 is:


n        n        n

image15.png= (3.8 ×105 )(u 2 ) + 3.28u

5        2

un+1  = (3.8 × 10   )(un


) + 3.28un


{11}

Table 4.1. Growth factor r=2.9. The population of fish in a lake over a time range of 20 years estimated using the logistic function model

{11}. The interval of calculation is 1 year.

Year

Population

Year

Population

1

1.0104

11

7.07104

2

2.9104

12

4.19104

3

6.32104

13

7.07104

4

5.56104

14

4.19104

5

6.49104

15

7.07104

6

5.28104

16

4.19104

7

6.73104

17

7.07104

8

4.87104

18

4.19104

9

6.96104

19

7.07104

10

4.42104

20

4.19104

Estimated magnitude of population of fish of a hydrolectric project during

the first 20 years by means of the logistic function model U n+1  {11}

70700

65700

60700

55700

image09.png50700

45700

40700

35700

30700

25700

20700

15700

10700

5700

700

-4300  0        1        2        3        4        5        6        7        8        9        10        11        12        13        14        15        16        17        18        19        20

image16.pngYear

12


IB Mathematics HL Type II Portfolio: Creating a logistic model        International School of Helsingborg – Christian Jorgensen

Figure 5.2. Growth factor r=2.9. Graphical plot of the fish population of the hydroelectric project on an interval of 20 years using logistic function model {11}.

With a considerably large growth rate, r=2.9, the long-term sustainable limit is reached after already 3 years, and since this limit cannot be surpassed over a long time, the fourth year is characterized by a drop in population (ie. the death of roughly thirty thousand fish), followed by a demographic explosion. This continues on until two limits are reached, with a maximum and a minimum value. Hence a dynamic systemis established. Instead of an asymptotic behaviour it goes

from the maximum to the minimum [between the very low (4.19x104) and the excessively high

(7.07x104)].

As previously explained, the population cannot remain that high and must thus stabilize itself, yet

this search for stability only leads to another extreme value. The behaviour of the population is opposite to that of an equilibrium in the population (rate of birth=rate of death)

...read more.

Conclusion

Two cases could occur:

a.   An external factor increases the mortality of the population.

b. The fish reproduced at a higher rate than the model predicts.

Also, one has not taken into account that despite the model having the long-term sustainability limit at

about 6x104, several factors could change this:

        Human action such as contamination of the habitat.

        Other aquatic vertebrates2 that might be positioned higher in the food chain, and could disturb the stability by consuming the studied fish’s own source of food.

        Season changes

        Global warming

Thus it would be wise to introduce a term into the model that takes into the account the long-term

sustainability limit, which in a non-ideal situation probably would change.

The model predicts a few interesting things:

        Overpopulating the lake in the first year leads to the death of all fish by the end of year one. The model is built for u1=1x104 fish, yet say one introduced one million fish in the lake (ignoring the capacity of the lake):

u        = (1× 105 )(u )2  + 1.6(u )

1+1        1        1

= (1× 105 )(1× 106 )2  + 1.6(1×106 ) =8.4 × 106  fish

        Populations that reproduce at a very high rate (ie. r=2.9) result in a dynamic limit (with two values instead of a stable limit with only one value) of fluctuations between the extrema, first from the maximum towards the minimum in only one year. This opposes the asymptotic behaviour predicted when the growth factor is smaller.

        When harvesting is introduced into a stable population (in this case at u1=6x104) only harvests below

9x103 fish may take place unless extinction of the population is desired.

        When the harvesting is set at constant value of 8x103, initial populations below a specific value

will grow in magnitude until approaching that value, while initial populations above that value (yet not above a certain limit as overpopulation causes death as well) lead to a decrease in magnitude

until approaching the same limit.

2 Biological term for fish: Wikipedia < http://en.wikipedia.org/wiki/Fish> Visited on 21. December 2006

29

...read more.

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