Designing a Freight Elevator

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Introduction

A heavy-duty freight elevator is used to raise and lower equipment and minerals in a mineshaft. Models are created to represent the movement of the elevator in terms of position. There are a number of specifications to take into consideration when creating a model and these will depend on the situation that the model is supposed to represent. To accommodate different specifications, different models are created with these specifications in mind.  

Analyzing a possible model

The formula y = 2.5t3 − 15t2 represents the position of the elevator, y, measured in meters (y = 0 represents ground level) and t represents time measured in minutes (t = 0 is the starting time). The trip up and down the shaft, ignoring time spent at the foot of the shaft, is approximately six minutes and that the depth of the shaft is no more than 100 meters.

By graphing the function (x = −1, y = 2.5t3 − 15t2) in parametric mode, one can better visualize the movement of the elevator down the shaft. The dot indicates where the function starts and stops as it runs from t = 0 to t = 6, zero to six minutes. The line represents the movement as it starts at ground level (y = 0) and descends down to a depth of 80 meters (y = 80) and then rising back up to ground level.

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The chart below shows the position of the elevator at different times:

By changing to function mode, we can take a better look at the position, velocity, and acceleration of the elevator.

Position Function:

In the position graph above, we see that the elevator starts at ground level,  reaches a height of 80 meters below, and goes back up to up to ground level, all in the course of 6 minutes.

Velocity Function:

By taking the derivative of the position function (y = 2.5t3 ...

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