Investigation of Area Under a Curve and Over a Curve

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        In this investigation I will be examining the relationships of the area under a curve and over a curve  between two specified limits. Here I will call A the area surrounded by  and the x-axis between the limits x=a and x= b. B on the other hand is the area defined by  And the y-axis between the limits and .  The vales of a and b will be whole real numbers. The investigation will test the ratio between A and B.

        Initially, I will begin by finding the ratio of A to B using a simple function, . The area of B is surrounded by this curve  and the x-axis from x = 0 to x = 1 (a=0 and b=1). The area of A will be surrounded by the curve , and the y-axis from To which are  y = 0 and y = 1. The graph below shows the graph of With the areas of A and B shaded respectively

Graph of

First I will find the area of B by using the formula of . This formula however translates into . In here a=0 and b=1 and .

Now that I have calculated the area of B I will calculate the area of A, but to do so there are 3 possible methods that can be used.

Method 1:

The first method consists of taking the area of the entire triangle formed by the boundaries and subtracting from it B, the area under the curve which we already found to be , hence leaving only the area of A.

Method 2:

The second method to find A is by subtracting the area underneath lower curve from the area of the top curve. Here I can use  as the top curve (b remains 1) and subtract from it the area of the lower curve of .

This method gave us the same area of A that the first method did.

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Method 3:

The final third method involves solving for x and finding the area in terms of y.

Now that the areas of both A and B have been calculated, a ratio can be obtained by dividing A by B.

The ratio of A to B is 2:1.

Next, I will find the ratio of A to B in other functions that follow the model of  and where n is a positive integer. The area will remain bounded by the curve as well as the x-axis from x=0 to x=1. Throughout the rest of ...

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