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# Math IA - Logan's Logo

Extracts from this document...

Introduction

 IBO INTERNAL ASSESMENT Logan’s Logo Mathematics SL Type II

Introduction

Logan has designed the logo at the right. The diagram shows a square which is divided into three regions by two curves. The logo is the shaded region between the two curves.

He wishes to find mathematical functions that model these curves.

In order to find these functions, we will need to overlay the logo on graph paper, so we can interpret data points to be able to plot them.

Take note that in the “modeling the data” in the next section, the logo was not resized, but set as transparent so that data points could be read.

Also, take into consideration the uncertainty of the measurements (± 0.25 units). For modeling purposes, the uncertainties are not included in the data calculations; however this should not be overlooked.

Modeling the Data

Note: Data tables and their graphs are included on the next page.

Top Curve :

In order to find a function to model the top curve, there are various methods that we can use. One is to overlay the logo onto a set of axes and estimate points for the function. Once we obtain these points, we can then plot them onto a new set of axes. Judging from the logo itself, at first glance it appears that a sine function would fit the data. The sine function would have to undergo a series of transformations to eventually fit the curve.

Using the axes and logo depicted above, I estimated 13 points for  and recorded them in the data table below:

NOTE: Due to the limited precision of the graph, I was only able to estimate to the nearest tenth. Maximum and minimum points have been shaded.

 X Y -2.5 -1.0 -2.0 -2.5 -1.6 -2.8 -1.0 -2.4 -0.5 -1.3 0.0 0.0 0.5 1.5 1.0 2.6 1.5 3.4 1.8 3.5 2.0 3.4 2.5 2.5 2.6 1.9

...read more.

Middle

Now we just need to restrict the domain and range to the parameters we set at the beginning of the investigation. The final graph is shown at the left.

The small adjustments we made at the end exhibited the error in our calculations to find the curve of best fit. This can, in turn, be attributed to the large uncertainty in obtaining the actual data. Because I was only able to read points off of the graph, smallest of 1 unit, my precision was limited to one decimal place, and the uncertainty was quite large (±0.5 units). Another limitation was the thickness of the line in the original logo. Because it was so thick, it was also hard to determine where exactly the points lied. This increased the uncertainty of our measurement. Therefore, small adjustments to the curve were needed at the end to ensure the function best matched the data.

Bottom Curve :

In order to find a function to model the bottom curve, we can also take the sinusoidal function approach.

Again, using the axes and logo depicted above, I estimated 13 points for  and recorded them in the data table below:

NOTE: Due to the limited precision of the graph, I was only able to estimate to the nearest tenth. Maximum and minimum points have been shaded.

 X Y -2.5 -3.1 -2.0 -3.5 -1.5 -3.4 -1.0 -2.6 -0.5 -1.8 0.0 -0.8 0.5 0.1 1.0 0.7 1.4 0.9 1.5 0.8 2.0 0.3 2.5 -1.0 2.6 -1.6

After determining these data points, I then plotted them onto a separate set of axes:

From here, it is obvious that a sine function would fit the data. A sine function can be defined as:

,

Where a represents the amplitude of the sine curve (or vertical dilation); b is the horizontal dilation; c is the horizontal shift; d is the vertical shift; and x and y

...read more.

Conclusion

bHorizontal shift– cVertical shift– d

Numbers 1 and 4 both stretch or shrink the curve parallel to the x-axis, which means that the amplitude a and vertical shift d will only be affected by the manipulated range (factor of or). On the other hand, numbers 2 and 3, the horizontal dilation and shift, will stretch or shrink the curve parallel to the y-axis. Again, this means that they will only be affected by the manipulated domain (factor ofor).

Now we are able to apply the corresponding shrink factors to their appropriate variables in order to obtain a new curve for Logan’s business cards.

Top Curve

The final equation for the top curve is given by the following equation:

with a period of 6.3.

Thus we must make the following changes to each of the variables. For a, the amplitude or vertical dilation factor:

For b, the horizontal dilation factor:

For c, the horizontal shift factor:

For d, the vertical shift factor:

Thus the final equation for the logo with dimensions compatible with that of a standard business card is:  with parameters of: and.

The graph of the manipulated curve is shown below, on a 9cm × 5cm business card.

Bottom Curve

The final equation for the top curve is given by the following equation:

with a period of 6.0.

Thus we must make the following changes to each of the variables. For a, the amplitude or vertical dilation factor:

For b, the horizontal dilation factor:

For c, the horizontal shift factor:

For d, the vertical shift factor:

Thus the final equation for the logo with dimensions compatible with that of a standard business card is:  with parameters of: and.

The graph of the manipulated curve is shown on the next page, on a 9cm × 5cm business card.

The final logo on the business card is shown below. Note that the dimensions are in units which, shown through the calculations above, have been converted to ensure they match the ratio and proportion of a standard business card.

| Page

...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Maths section.

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