- Level: International Baccalaureate
- Subject: Maths
- Word count: 1085
Math Portfolio: Fishing Rod
Extracts from this document...
Introduction
Ismar Hota
Math Portfolio: Fishing Rod
The table shown below shows the distance for each of the line guides from the tip of the fishing rod.
x | Guide number (from tip) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
y | Distance from tip (cm) | 10 | 23 | 38 | 55 | 74 | 96 | 120 | 149 |
The information in the above table can be presented on a XY graph; where guide number is shown on X axis and the distance from the tip is shown on the Y axis. (See graph below)
From this graph one can come to a conclusion that the points represent a part of a quadratic function. A matrix method ( ) will be used to define parameters of the quadratic function ( ) using a given points (table above).
The matrix method:
Points: (1,10); (2,23); (3,38)
a + b + c = 10
4a + 2b + c = 23
9a + 3b + c = 38
=>
From matrix result it follows:
a = 1
b = 10
c = -1
When plugged back to the , the result is quadratic function
From the graph it is visible that the first five points fits the quadratic function exactly however afterwards the points don’t correspond the curve.
Middle
23
38
55
74
96
120
149
Distance from tip (cm)
10.5417
22.7321
37.4107
54.5774
74.2321
96.375
121.006
148.125
This allows for a conclusion to be made that the function better fits the model than the that was proved using the matrix method. Although the first one lacks correspondence with the all of the points it is to a very slight value and can be said that it gives a more reasonable result. Even though corresponds exactly for the first five points afterwards the correspondence difference grows to a bigger value and the reliability of this function is low (see graph below).
x | Guide number (from tip) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
y | Distance from tip (cm) | 10 | 23 | 38 | 55 | 74 | 96 | 120 | 149 |
Distance from tip (cm) | 10.5417 | 22.7321 | 37.4107 | 54.5774 | 74.2321 | 96.375 | 121.006 | 148.125 | |
Distance from tip (cm) | 10 | 23 | 38 | 55 | 74 | 95 | 118 | 143 |
To calculate the guide for point 9 we will have to substitute 9 into the equation(s) giving the value of 170. The second function gives the value of 177.7321
The implication with this is that we cannot with certainty tell where the best place for the 9th point is. This is the limit
Conclusion
Points: (1,10); (3,34); (5,64)
a + b + c = 10
9a + 3b + c = 34
25a + 5b + c = 64
=>
Here when using the matrix method we find out that the value for a mustn’t equal zero because then the function that is a result of that is a linear one which will make the curve completely unreliable and for that reason the values that were used for determining the equation are the 1st 3rd and 5th.
This means that by guessing and trying method one can come to a more reliable result, which will correspond more closely using the matrix method.
Conclusion:
This method is probably used by the factories that make fishing rods. They could use this to manufacture a long lasting rod that would be able to catch many heavy fish and be resistant to breaking or damages. I can see this be used in building of many items that have a spring or other like objects where their endurance needs to be tested. This model seems like a reasonable method to be used by mechanical engineers when observing items so they can be ready to hit the market as a final product.
This student written piece of work is one of many that can be found in our International Baccalaureate Maths section.
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