Stellar Numbers. In this study, we analyze geometrical shapes, which lead to special numbers. We consider various geometrical patterns of evenly spaced dots and derive general statements of the nth special numbers in terms of n.

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Timur Karimov

Anglo – American School of Moscow

IB Mathematics

Internal Assessment Portfolio Practice 1


Aim: The aim in this task is to consider geometric shapes, which lead to special numbers. The simplest examples of these are square numbers, 1, 4, 9, and 16, which can be represented by squares of side 1, 2, 3 and 4.

Introduction: In this study, we analyze geometrical shapes, which lead to special numbers. We consider various geometrical patterns of evenly spaced dots and derive general statements of the nth special numbers in terms of n. Henceforth, all tables and mathematical formulas are generated by the Microsoft Word. All the stellar and triangular number visual representations are modulated using GeoGebra 4. The rest of the shapes are generated by “insert shape” function of Microsoft Word.

Task 1

The first task is to complete the triangular numbers sequence with three more terms.

As we can see, each successive triangle pattern numbered  (n is the stage number) can be derived from the previous one number () by simply adding  evenly spaced dots on either of the sides of the triangle.

In other words, the number of dots in the triangular number n equals to the number of dots in the triangular number ) plus . Lets denote this number by Gn

Using this formula, we can calculate the number of dots in the triangular number 6:

 

In the triangular number 7:

And in the triangular number 8:


and etc.

The following table can demonstrate this sequence:

The last 3 triangular numbers can be graphically demonstrated as following.

Using the expression  one can continue the triangular number sequence indefinitely.

Task 2

Find a general statement that represents the nth triangular number in terms of n.

In the previous task, we defined the nth triangular number  in terms of the previous triangular number

In this task we can derive a more general statement that represents the nth triangular number only in terms of n. One can consider the rectangular structure that is comprised of two equivalent triangular structures. By merging two triangular shapes, one can produce a parallelogram shape

        

By further checking for the duplication of the diagonal, one can represent this structure as a parallelogram shape, where each side has n dots. Thus, the total number of dots of the two combined identical triangular structures equals to n2 plus the additional number of dots in the extra diagonal n. In other words:

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or

Lets check this general statement with the following table:

One can confirm from this table that the general formula of the nth triangular number in terms of n provides exactly the same results as the consecutive formula from Task 1. Finally, one can confirm that the two formulas are identical by the following calculation:

Substituting with the general statement:

  and   (n-1)

Opening the brackets, one can see that the two sides are identical; therefore the general formula for n is the same as the consecutive ...

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