Stellar numbers. This internal assessment has been written to embrace one of the rather inquisitive aspects of mathematics, stellar numbers

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IB Math SL

Mr. Doty

11 September 2011

Internal Assessment 1: Type 1

        Stellar Numbers        

This internal assessment has been written to embrace one of the rather inquisitive aspects of mathematics, stellar numbers.A stellar number is a numerical value for the total number of dots that can be positioned within a designated geometric shape with a determined number of vertices.This paper will consist of a panoptic yet concise set of instructions involving the use of technology, primarily a graphic calculator and a computer, for the reader to fully appreciate how this candidate analyzed the patterns of various examples of triangular and stellar numbers to formulate a conclusive general statement regarding the variables p, the number of vertices, and n, the term of the stellar number.

In mathematics, it is essential that the learner is able to distinguish a pattern within a set of numbers, define the pattern using words, and carry on the pattern. A series of numbers in which a pattern is present is called a number sequence. The numbers in the sequence are called its members or its terms. A number sequence can be defined with the use a formula which represents the general term or also known as the nth term.The formula is useful for determining the value of the nth term without actually having to count out and write down every single member of the sequence. With this concept of number patterns and sequences of numbers, a general statement will be produced which will generate the sequence of p -stellar numbers for any value of p at any term, n.

First, this investigation will deal with triangular numbers. A triangular number is the total sum of the dots in an equilateral triangular pattern of evenly spaced dots. The following representations display a sequenceof such numbers to aid the reader with the visualization of such figures:

Figure 1

Figure 1 consists of diagrams for the first 5 terms of the triangular numbers. Now that the reader is familiarized with what triangular numbers are and what they look like, let’s look at the possible patterns which may arise from this sequence of numbers.

Table 1

Table 1, to the left, shows the results of the data obtained by counting and calculating the number of dots in each triangular number tested, wheren is the term, y is the total number of dots and the 1st and 2nd differences are self-explanatory.With a mere glance at the total number of dots, y, one might not notice the pattern immediately. The next aspect to be inspected is the 1st difference of y. The 1st difference between consecutive values of yis not constant thus eliminating the possibility of the general statement being a linear one, in the form of y=mx+b. However, the 1st difference does seem to be increasing at a constant rate for each input of n. Looking at the 2nd differences, it can be observed that the change is constant for all values. A common 2nd difference among the points suggests that the series can be represented by a quadratic equation.A quadratic functionis given by the following equation, y=ax2+bx+c, where a≠0. Thus, to find the expression for this sequence of numbers, the quadratic function has to be calculated.There are numerous ways one can find the quadratic equation given a set of x and y values, but in this task, technology will be used to derive the formula. With the aid of a TI-84 Plus graphic calculator a quadratic equation will be formed. Using the graphic calculator:

  1. Select STAT 1: Edit…
  2. Input the appropriate values for n and  y under L1 and L2 respectively
  3. Select STAT  CALC  5: QuadReg ENTER

Figure 2

Figure 2, to the left, shows what the TI-84’s display should look like after following the previous steps above.By substituting the appropriate values for a, b, and c, the following equation is formulated:

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y= 12x2+ 12x

The general statement has to be in terms of n, not  but beforehand, this equation can be further simplified. The common factor of 12 can be factored out:

y= 12(x2+ x)                

whichcan be rewritten as division rather than multiplication:

y=(x2+x2)        

Since x is equivalent to nas they represent the same variable, therefore x=n,n is substituted in the equation, thus the general statement regarding triangular numbers is formed:

wheren∈N.y represents the total number of dots and n represents the term of the triangular number.

Table 2

        However, this is not the only way such a statement can be generated. The pattern of ...

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