• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month
  1. 1
  2. 2
  3. 3
  4. 4
  5. 5
  6. 6
  7. 7
  8. 8
  9. 9
  10. 10
  11. 11
  12. 12
  13. 13
  14. 14
  15. 15

type 1 maths portfolio trapezium rule

Extracts from this document...


image00.pngThere are different ways through which can estimating the area under a curve of a certain function and one of the many methods is by the trapezium rule.

The area of a trapezium (trapezoid) is determined by;

image01.png Or in words, the average of twoimage00.pngsides times the base, which could also be expressed as image141.png where by if considering trapeziums formed under a curve; parallel image48.pngintervals form the sides and image22.png the base, which also doubles as the height.

To determine the area under the functionimage24.png, with in the interval ofimage168.png,image177.png, one can estimate the area by trapeziums over subintervals by finding the image22.png.image00.pngimage12.png

In the first attempt approximate an area the curve of the given function above, two trapeziums will be considered.


The height (h) in this case, is the difference between the X intervalsimage41.png

Therefore, for the two trapeziums, h =image00.pngimage41.png is determined by;

image72.png, Where by n is the number of trapeziums or intervals.

So, we know b is 1 and a is 0 comparing to the integrals of the function,


                                 So now, image72.png



            Giving usimage113.png, as our height (h)

NB:image41.png, 0.5 is considered to be the height because the trapezoids are rotated image133.png which makes their base the height.

To be able to calculate the area of both trapeziums, we have to consider all the lengths required hence, image136.png

We will therefore have to find the values of Y intervals, which form image137.pngsides.

...read more.


with corresponding ordinatesimage175.png.

If we consider an area of under a curve on the interval image176.png

The interval could be divided into subintervals using image13.png


And then construct trapeziums over each sub interval,  

The sum of the trapezoids constructed will probably give an approximation of an area under the curve on the interval image00.pngimage179.png

The new base (h) will therefore be,


And the sides will be,




  Having found all the sides,image48.png and image22.pngwhich also doubles as the base or height, we can now approximate the areas of each trapezium.

Therefore area will be as follows




Therefore, total approximation area for image13.pngtrapeziums



Comment; having estimated the area using 2, 5 and 10 trapeziums respectively, it can be noticed that the more trapeziums one uses to draw a conclusion, the nearer or the better approximation one gets. I.e. the more trapeziums one uses to approximate an area under a curve, the nearer you come to the solution got when u use the function to determine the area.

For instance, when two trapeziums are considered, the approximation is image17.png which makes a big difference from the area derived when using the function.

Also when 5 trapeziums are considered, the approximation is image18.png which also gives a greater difference of 1.002

But then it can be proved that the greater number of trapeziums one considers approximating the area under a curve, the more accurate answer you arrive at.

...read more.


image81.pngand image82.png are put in the given functions instead for image21.png will give different results.

For the function image83.png,


we can split the area covered under the curve formed by the function to estimate its area.

Y intervals, which form the other sides of the formed trapeziums, are crucial in estimating the trapezium areas. They form what in the formulae is image74.png



Knowing all the necessary sidesimage22.pngand theimage48.pngintervals, its then possible to estimate the area of every trapezium, the results give us, by applying the sides to the formulae of finding the area of trapeziums image94.png where in our case we consider; image96.png

Therefore, approximation for the areas of image73.png trapeziums gives the following results.


Therefore total approximation area will be; image101.png

This gives us the an approximation of image102.png

For the function image103.png, knowing the height whichimage22.png the sides will be,


The same procedure can apply to the above functions and other function as well to estimate their areas using trapezoids are the image74.pngsides keep on varying depending on the structure of the curve formed, we always have to find news sides to that function but image22.pngsupposing the functions are in the same range.




The area estimated areas are as follows;




The total approximation of the areas will therefore be;




For the function image122.png


The y intervals of the new function will then be;


Having known all the required sides image22.pngimage129.pngits then possible to estimate the areas of all the eight trapeziums formed under the curve.

Therefore the areas,


Which gives a total approximation area image119.png


...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Maths section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Maths essays

  1. Math Portfolio Type II Gold Medal heights

    104 108 112 Height in cm 234 235 236 236 Table 2.1 Data table for the height of the gold medallists in high jump from 1896 until 2008, with year 1896 as year 0. In order to be able to rate how well the graph is fitted to depict the

  2. Mathematics (EE): Alhazen's Problem

    In Figure 10, it is apparent that ? = � - ? and that � = ? - �. Also, from the diagram we can derive that: Since angle ?

  1. Math Portfolio: trigonometry investigation (circle trig)

    again with 9 coordinates. Upon the analysis of the pattern of the graph, As the value of ? increases from - to -, cos? goes from 1 to 0. As the value of ? increases from - to -, cos? goes from 0 to -1. As the value of ?

  2. Shady areas; math portfolio type 1

    [first height + 2(sum of all middle heights) + last height] So the general expression in this case for n trapeziums is: Area = 1/2 (x) [g (0) + 2(g (x1) + g (x2) +................+ g (xn-1)) + g (1)] [OBS!

  1. Math portfolio: Modeling a functional building The task is to design a roof ...

    Coordinate of C= (36+V, y(36+V) ) y(36-V) is the height of the cuboid "H" Substituting (36-V) into equation (5) y(36-V) = (36-V)2 + 2(36-V) = [(36-V)2 - 72(36-V)] = (36-V) (36-V-72) =(36-V) (36+V) y(36-V)=(1296-V2) --------------(6) The volume of the cuboid = length � width � height Volume = 150 � 2v � (1296-V2)

  2. Investigating ratio of areas and volumes

    y = xn between the points x = 1 and x = 2: Area A will be the area contained between the graph of y = xn and the x-axis between the points x = 1 and x= 2. Area B will be the area contained between the graph of

  1. High Jump Gold Medal Heights Type 2 Maths Portfolio

    Linear Model Graph 2: The winning heights of Olympic Games against years since 1932 (between 1932 and 1980) In order to make calculations easier, I created a graph of height versus years since 1932 as seen in graph 2. When considering the trends and possible functions this graph models, I

  2. Maths portfolio Type- 2 Modeling a function building

    So AE is equal to ED which is also equal to x We know that OE=36 meters Therefore OA=36-x Thus A?s coordinate= (36-x,0) Likewise the coordinate of D will be=(36+x,0) Since the cuboid b and c are falling on the curved structure so the B coordinate = (36-x, y)

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work