• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

centripetal force lab (DCP, CE)

Extracts from this document...

Introduction

Centripetal Force

Aim: To investigate the relationship between the rotation period T and the hanging mass M when an object is moving at a constant speed in circular motion.

Variables:

Independent variable

Hanging mass

Dependent variable

Rotation period

Control variables

- Number of rotation period

- Length of string

- Mass of the rubber stopper

- Friction/ air resistance

Apparatus:

Meter stick, electric balance, timer, strings, rubber stopper, mass, plastic tube

Method:

image00.png

Data Collection


length of the string L = 35.0 cm ± 0.1cm = 0.350 m ± 0.001 m
mass of the rubber stopper = 38 g ± 1g = 0.038 kg ± 0.001 kg

The uncertainty of the string’s length, mass of the rubber stopper and time is taken to the smallest division of the measuring device (meter stick to measure length of string, electric balance to measure mass of stopper, stopwatch to measure time taken to complete 10 rotation period).


Raw Data

hanging mass/ g ± 1g

time taken for 10 rotation/ s ± 0.01s

Average time for 10 rotation/ s ± 0.01s

Random uncertainty In t (±s)

1st trial

2nd

3rd

4th

5th

50

7.01

7.79

7.37

7.68

7.26

7.42

0.16

100

5.84

5.21

5.41

5.96

6.04

5.69

0.17

150

5.16

4.79

5.35

4.70

4.97

4.99

0.13

200

4.78

4.66

4.50

4.12

4.83

4.58

0.14

250

3.82

4.01

4.41

4.68

4.22

4.23

0.17

300

3.62

3.77

4.06

3.93

4.28

3.93

0.13

Mean

0.15

The random uncertainty of the average time taken for 10 rotations is calculated by image01.pngimage01.png

Eg. Random uncertainty for time taken for 10 rotation period when the hanging mass is 50.0 kg = (7.79-7.01)/5=0.16

Data processing

Mass

...read more.

Middle

0.100

0.58

0.52

0.54

0.60

0.60

0.57

0.02

0.150

0.52

0.48

0.54

0.47

0.50

0.50

0.01

0.200

0.48

0.47

0.45

0.41

0.48

0.46

0.01

0.250

0.38

0.40

0.44

0.47

0.42

0.42

0.02

0.300

0.36

0.38

0.41

0.39

0.43

0.39

0.01

Mean

0.02

image11.png

From the graph, the best fit is does not pass through the origin and it is more like a negative curve. This may suggest a positive linear relationship between image04.pngimage04.png and the hanging mass M.

Time

In order to have a linear graph, I have to plot image04.pngimage04.png against the hanging mass. The average time taken for 1 period of each mass have to be processed to image04.pngimage04.png.

For example, the rotation period when mass is 0.050 kg, is 0.74s. Thenimage02.png

Final Data

Hanging Mass/kg ± 0.001 kg

image03.png ± 0.

...read more.

Conclusion

        The timing process of the rotation period causes a major random uncertainty in this experiment. Since there isn’t a certain point indicating the start and end of a rotation, timing the rotation period involve estimation of the starting/ending point of the rotation and may cause uncertainty.

        Reaction time when using the stopwatch also causes uncertainty. A person cannot start or stop the stopwatch exactly at the point where rotation starts. The reaction time can be kept constant by having the same person as the timer throughout the experiment. However, in most cases, the reaction time starting and stopping the stopwatch may not always be equal and cannot fully cancel each other out. The percentage uncertainty can be reduced by timing more rotation period to reduce the significance of the reaction time on the data.

...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Physics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Physics essays

  1. Period of a loaded Cantilever (D, DCP, CE)

    0.05 cm Raw Data Mass loaded on the cantilever g � 0.05g Time taken for 10 oscillations � 0.005s Average time taken 10 period of oscillation � 0.005s Random uncertainties � s 1st trial 2nd 3rd 4th 5th 50.0 2.63 1.94 2.31 2.34 2.16 2.28 0.3 100.0 2.72 2.56 2.54

  2. Boyle's law report (DCP, CE)

    Maximum gradient = Minimum gradient = Best-fit gradient = (0.40+0.34)/2 = 0.37 kPa-1 dm-3 � 0.03 kPa-1 dm-3 Conclusion The final graph show a linear relationship between V and and it is possible to draw a line through the origin within the uncertainty range, which suggest a inversely proportional relationship between volume and pressure of gas.

  1. Investigate the factors affecting the period of a double string pendulum

    And the period of the metal bar is inversely proportional to the distance l between the two strings. Finally, if I had used a wider range of distances between the two strings (l in cm) then I would have been able to continue my graphs and perhaps find a different

  2. Centripetal Force

    ?t = �0.005 s 1 6.47 2 7.47 3 6.91 4 7.44 5 7.00 6 7.32 7 6.35 8 7.50 9 7.79 10 8.47 Table 3.3 Result of Time taken for 10 revolutions for mass 30 g Trial Time Taken t(s)

  1. Analyzing Uniform Circular Motion

    kg Time Period for 10 cycles(�0.01s) Period for 1 cycle (�0.001s) 0.014 4.35 0.435 4.75 0.475 0.020 5.53 0.553 5.31 0.531 0.028 6.21 0.621 6.14 0.614 0.034 6.54 0.654 6.73 0.673 0.040 7.05 0.705 6.93 0.693 Controlled Variables: Radius = 0.36 � 0.0005 m Hanging Mass = 0.06211 � 0.00001 kg Data Table # 3: Manipulating Hanging Mass (Mh)

  2. Determination of Coefficient of Friction

    = ?l/l + ?h/h -> ?? = ? (?l/l + ?h/h) ?? = 15.6 (0.1/51.3 + 0.3/13.8) = 0.4� ?? = 0.4� ?? = 0.4� ?? = 0.4� ?? = 0.4� Now I will find the static coefficient of friction.

  1. Physics Spinning Stopper Lab

    of mark by the marker was used on the string to indicate where the length of the spring was supposed to be kept at when the stopper was spinning. * (Average Time uncertainty) = ((Max Time)-(Min Time))/2 = (3.2-2.8)/2 = 0.2s.

  2. How does the sinkage depth of a tyre affect its rolling resistance ?

    ramp of length 5 meters and width 3 metres inclined at an angle of 45° to the ground . The bicycle after rolling down from the ramp rolled on a sand bed that was smoothened and softened by hand .

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work