• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Hooke's Law

Extracts from this document...

Introduction

Hooke’s law: determining k for a spring

Aim:

To investigate Hooke’s law for simple springs of rubber

Hypothesis:

The relationship between a load force and a light spring (F=k.x) was first determined by Robert Hooke in the 17th century.Where F is the force applied to the spring, k is the spring constant, and  x is the extension of the spring. Hooke’s law states that when an elastic material is subjected to a force, its extension (x) is proportional to the applied force. The value of k is constant for a particular spring.

Variables:

 Independent Controlled Dependent Different type of spring used (varied by using different springs) Weight of the mass attached (controlled by using only one mass) Spring constantExtension by the spring (measure by ruler)

Materials:

 Item Quantity Accuracy Spring with different stiffness 5 - Retort stand and clamp 1 - Meter rule or other measuring devices 1 ±0.005 m Mass hanger 1 - 50 gr masses 10 Δm ±0.05 gr balance 1 -

Methods:

1. First weigh and record the masses of each mass hanger and the masses
2. Record these in a suitable for reference during the activity

Middle

0.144

3

0.15

0.145

4

0.20

0.184

5

0.25

0.240

6

0.30

0.291

7

0.35

0.350

8

0.40

0.402

9

0.45

0.469

10

0.50

0.524

Table 3.6 Data of spring 5 extension

 Trial (n) Massm (kg) Suspended Lengthx2 (m)Δx2=±0.0005m 1 0.05 0.179 2 0.10 0.196 3 0.15 0.221 4 0.20 0.246 5 0.25 0.274 6 0.30 0.301 7 0.35 0.328 8 0.40 0.355 9 0.45 0.381 10 0.50 0.412

Data processing:

k= (Δm/Δx) x g

Table 4.1 Data of spring 1 extension

 Trial(n) Massm (kg) Pulling forceF (N) Suspended Lengthx2 (m)Δx2=±0.0005m 1 0.05 0.49 0.140 2 0.10 0.98 0.141 3 0.15 1.47 0.145 4 0.20 1.96 0.177 5 0.25 2.45 0.235 6 0.30 2.94 0.289 7 0.35 3.43 0.346 8 0.40 3.92 0.401 9 0.45 4.41 0.465 10 0.50 4.90 0.533 Spring’s constant: Table4.2 Data of spring 2 extension

 Trial(n) Massm (kg) Pulling forceF (N) Suspended Lengthx2 (m)Δx2=±0.0005m 1 0.05 0.49 0.158 2 0.10 0.98 0.158 3 0.15 1.47 0.172 4 0.20 1.96 0.236 5 0.25 2.45 0.292 6 0.30 2.94 0.367 7 0.35 3.43 0.426 8 0.40 3.92 0.487 9 0.45 4.41 0.558 10 0.50 4.90 0.635 Spring’s constant: Table4.

Conclusion

th spring that is very stiff (18.679) and on the other hand in 3rd spring that is the least stiff (3.584).

The difficulties encountered in conducting this experiment is when measuring the extension of the spring, as the spring tend to swings when the mass is attached and this can affect the result of the experiment. In addition, the extension of the spring occasionally hits the floor when the number of mass is increased and this affected the results. This difficulty has been solved by using a retort stand and clamp, which give an increase the stretch of the spring but still easily adjusted.

In conclusion, it could be said that the experiment is successful in verifying value of the spring constant. Both the Hooke's law and the graph give similar result, thus proving the hypothesis. My suggestion to improve the experiment is to carefully measure the extension of the spring despite the variation of the spring. This is best dealt with by carefully observed the spring until it places perfectly so that there will be no further movements that may lead to the mistake in calculating the exact extension of the spring.

This student written piece of work is one of many that can be found in our International Baccalaureate Physics section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related International Baccalaureate Physics essays

1. ## Aim: To prove the parallelogram law of vector addition

It could also be caused by existence of friction between the string and the pulley wheel which is not taken into account here. Errors could also be caused when we are using a protractor to measure the angle between the two forces.

2. ## This is a practical to investigate the relationship between time period for oscillations and ...

Evaluation: From the graph we can see that the results are fairly accurate as the line of best fit passes through all the points including the origin and hence there are no anomalous points. A considerable amount of error is expected to occur during the experiment and therefore the error

1. ## Suspension Bridges. this extended essay is an investigation to study the variation in tension ...

The weight of the bob acts vertically downwards and the two tensions can be resolved into their horizontal and vertical components. The summation of all vertical forces, and also the horizontal forces . Using this property, the formula to calculate the tension T1 is found out to be T1 =

2. ## Centripetal Force

0.550432 0.053955 0.0029112 6.16 0.616 1.623377 2.635352 0.583070 0.086593 0.0074984 6.90 0.690 1.449275 2.100399 0.464712 -0.031765 0.0010090 7.59 0.759 1.317523 1.735867 0.384060 -0.112417 0.0126375 6.81 0.681 1.468429 2.156283 0.477076 -0.019401 0.0003764 7.78 0.778 1.285347 1.652117 0.365530 -0.130947 0.0171470 6.67 0.667 1.49925 2.247752 0.497314 0.000837 0.0000007 ?Fc= 4.964767 0.1119149 Average centripetal

1. ## Hooke's Law Intro and data processing

some points' error bars do not touch the line of best fit, the maximum line, or the minimum line. This can all be due to random errors within the experiment. While measuring the length of the stretched spring, it was very hard to obtain an exact value of the full extension of the spring.

2. ## Finding the Spring Constant

For example, for the 100g mass, we weighed it and found that it was 90 something. After weighing all 7 masses, 96 was the lowest mass so 4g was the uncertainty. Thus it is � 4g. For the next masses, it would be � 8 and � 12 and so forth.

1. ## Hook's law. Aim of the experiment: To understand the Hookes Law by calculating the ...

The spring constant is found to be 36.42 N/m. So we can conclude that if we had the situation to put a weight of 36.42 N at the end of the spring the elongation would be one meter. Sources of Error: * Poorly calibrated instruments * The inevitability of air resonances and different conditions in the lab.

2. ## Hookes Law- to determine the spring constant of a metal spring

on 4 cm), as well as the same masses are used for each spring. The expected findings of this experiment is that the spring with the largest spring constant will extended least with the same amount of force applied. Therefore, the variation of the spring constant causes variation of extensions of different springs at the same amount of added-force. • Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to 